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Find the Z-transform of y(n) = x(n + 2)u(n).
  • a)
    z2 X(Z) + z2 x(0) – zx(1)
  • b)
    z2 X(Z) – z2 x(0) – zx(1)
  • c)
    z2 X(Z) – z2 x(0) + zx(1)
  • d)
    z2 X(Z) + z2 x(0) + zx(1)
Correct answer is option 'B'. Can you explain this answer?
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Find the Z-transform of y(n) = x(n + 2)u(n).a)z2 X(Z) + z2 x(0) &ndash...
Given y(n) = x(n + 2)u(n)

Let n + 2 = p,i.e. n = p – 2

=z2 X(Z) – z2 x(0) – zx(1).
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Find the Z-transform of y(n) = x(n + 2)u(n).a)z2 X(Z) + z2 x(0) &ndash...
To find the Z-transform of y(n) = x(n - 2)u(n), we can use the time-shifting property of the Z-transform:

Y(z) = X(z)z^{-2} * 1/(1-z^{-1})

where X(z) is the Z-transform of x(n), and the z^{-2} term comes from the fact that y(n) is x(n-2).

To find z^2 X(z), we can simply multiply Y(z) by (1-z^{-1}):

z^2 X(z) = Y(z) * (1-z^{-1})

z^2 X(z) = X(z)z^{-2} * (1-z^{-1})^2 / (1-z^{-1})

z^2 X(z) = X(z)z^{-2} * (1-2z^{-1}+z^{-2}) / (1-z^{-1})

z^2 X(z) = X(z) * (1-2z^{-1}+z^{-2}) / (1-z^{-1})

Finally, we can substitute x(0) for X(z) to get:

z^2 X(z) = x(0) * (1-2z^{-1}+z^{-2}) / (1-z^{-1})
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