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The electric field intensity E, due to an electric dipole of moment p, at a point on the equatorial line is
- a)parallel to the axis of the dipole and opposite to the direction of the dipole moment p
- b)perpendicular to the axis of the dipole and is directed away from it
- c)parallel to the dipole moment
- d)perpendicular to the axis of the dipole and is directed towards it
Correct answer is option 'A'. Can you explain this answer?
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The electric field intensity E, due to an electric dipole of moment p,...
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The electric field intensity E, due to an electric dipole of moment p,...
Explanation:
The electric field intensity (E) due to an electric dipole at a point on the equatorial line can be determined by considering the individual contributions of the positive and negative charges that make up the dipole.
1. Electric Field Due to Positive Charge:
At a point on the equatorial line, the positive charge of the dipole is closer to the point compared to the negative charge. Therefore, the electric field produced by the positive charge at the point will be directed away from the positive charge.
2. Electric Field Due to Negative Charge:
Similarly, at the same point on the equatorial line, the negative charge of the dipole is farther from the point compared to the positive charge. Therefore, the electric field produced by the negative charge at the point will also be directed away from the negative charge.
3. Net Electric Field:
The electric field due to the positive and negative charges at the point can be determined by vector addition. Since the electric fields due to the positive and negative charges are directed away from their respective charges, the net electric field at the point will be in the same direction as the electric field due to the positive charge.
4. Direction of the Electric Field:
The direction of the net electric field at a point on the equatorial line is parallel to the axis of the dipole and opposite to the direction of the dipole moment (p). This is because the electric field due to the positive charge dominates at this point, as it is closer and has a stronger effect compared to the negative charge.
Therefore, the correct answer is option 'A': The electric field intensity (E) due to an electric dipole of moment (p) at a point on the equatorial line is parallel to the axis of the dipole and opposite to the direction of the dipole moment (p).
The electric field intensity (E) due to an electric dipole at a point on the equatorial line can be determined by considering the individual contributions of the positive and negative charges that make up the dipole.
1. Electric Field Due to Positive Charge:
At a point on the equatorial line, the positive charge of the dipole is closer to the point compared to the negative charge. Therefore, the electric field produced by the positive charge at the point will be directed away from the positive charge.
2. Electric Field Due to Negative Charge:
Similarly, at the same point on the equatorial line, the negative charge of the dipole is farther from the point compared to the positive charge. Therefore, the electric field produced by the negative charge at the point will also be directed away from the negative charge.
3. Net Electric Field:
The electric field due to the positive and negative charges at the point can be determined by vector addition. Since the electric fields due to the positive and negative charges are directed away from their respective charges, the net electric field at the point will be in the same direction as the electric field due to the positive charge.
4. Direction of the Electric Field:
The direction of the net electric field at a point on the equatorial line is parallel to the axis of the dipole and opposite to the direction of the dipole moment (p). This is because the electric field due to the positive charge dominates at this point, as it is closer and has a stronger effect compared to the negative charge.
Therefore, the correct answer is option 'A': The electric field intensity (E) due to an electric dipole of moment (p) at a point on the equatorial line is parallel to the axis of the dipole and opposite to the direction of the dipole moment (p).
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The electric field intensity E, due to an electric dipole of moment p, at a point on the equatorial line isa)parallel to the axis of the dipole and opposite to the direction of the dipole moment pb)perpendicular to the axis of the dipole and is directed away from itc)parallel to the dipole momentd)perpendicularto the axis of the dipole and is directed towards itCorrect answer is option 'A'. Can you explain this answer?
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The electric field intensity E, due to an electric dipole of moment p, at a point on the equatorial line isa)parallel to the axis of the dipole and opposite to the direction of the dipole moment pb)perpendicular to the axis of the dipole and is directed away from itc)parallel to the dipole momentd)perpendicularto the axis of the dipole and is directed towards itCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The electric field intensity E, due to an electric dipole of moment p, at a point on the equatorial line isa)parallel to the axis of the dipole and opposite to the direction of the dipole moment pb)perpendicular to the axis of the dipole and is directed away from itc)parallel to the dipole momentd)perpendicularto the axis of the dipole and is directed towards itCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The electric field intensity E, due to an electric dipole of moment p, at a point on the equatorial line isa)parallel to the axis of the dipole and opposite to the direction of the dipole moment pb)perpendicular to the axis of the dipole and is directed away from itc)parallel to the dipole momentd)perpendicularto the axis of the dipole and is directed towards itCorrect answer is option 'A'. Can you explain this answer?.
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