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If f is a function of real variable x satisfying f(x + 4) – f(x + 2) +f(x) = 0, then f is a periodic function with period:
  • a)
    6
  • b)
    8
  • c)
    10
  • d)
    12
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
If f is a function of real variable x satisfying f(x + 4) – f(x + 2) ...
f(x + 4) – f(x + 2) + f(x) = 0 f(x + 6) – f(x + 4) + f(x + 2) = 0
∴ f(x + 6) + f(x) = 0
⇒ f(x + 12) + f(x + 6) = 0
∴ f(x + 12) = f(x)
⇒ f(x) is periodic with period 12.
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Most Upvoted Answer
If f is a function of real variable x satisfying f(x + 4) – f(x + 2) ...
Given:
- f(x+4) - f(x+2) + f(x) = 0

To find:
- The period of the function f(x)

Solution:
To determine the period of the function, we need to find a value T such that f(x+T) = f(x) for all real values of x.

Step 1:
Let's consider a new variable y = x + 4. This implies x = y - 4.

Substituting the value of x in the given equation, we get:
f(y) - f(y - 2) + f(y - 4) = 0

Step 2:
Now, let's consider another new variable z = y - 2. This implies y = z + 2.

Substituting the value of y in the equation obtained in step 1, we get:
f(z + 2) - f(z) + f(z - 2) = 0

Step 3:
Now, if we compare the equations obtained in step 1 and step 2, we can observe that:
f(z) = f(z - 2) - f(z + 2)

Step 4:
Let's consider a new variable w = z - 2. This implies z = w + 2.

Substituting the value of z in the equation obtained in step 3, we get:
f(w) = f(w - 2) - f(w + 2)

Step 5:
If we compare the equations obtained in step 3 and step 4, we can observe that:
f(w) = f(w - 2) - f(w + 2) = f(z) = f(z - 2) - f(z + 2)

Step 6:
Now, let's consider a new variable v = w + 2. This implies w = v - 2.

Substituting the value of w in the equation obtained in step 5, we get:
f(v - 2) = f(v - 4) - f(v)

Step 7:
Comparing the equations obtained in step 5 and step 6, we can observe that:
f(v - 2) = f(v - 4) - f(v) = f(w) = f(w - 2) - f(w + 2)

Step 8:
Considering a new variable u = v - 4. This implies v = u + 4.

Substituting the value of v in the equation obtained in step 7, we get:
f(u) = f(u - 2) - f(u + 4)

Step 9:
Finally, let's compare the equations obtained in step 7 and step 8:
f(u) = f(u - 2) - f(u + 4) = f(v - 2) = f(v - 4) - f(v)

Conclusion:
From step 9, we can observe that f(u) = f(u - 2) - f(u + 4) = f(v - 2) = f(v - 4) - f(v) = f
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If f is a function of real variable x satisfying f(x + 4) – f(x + 2) +f(x) = 0, then f is a periodic function with period:a) 6b) 8c) 10d) 12Correct answer is option 'D'. Can you explain this answer?
Question Description
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