DIRECTIONSfor the question:Solve the following question and mark the b...
Let f(x) = ax
2 + bx + c
► F(2) = 10 → 4a + 2b + c = 10
► F(0) = 4 → c = 4.
will be 0, 2ax + b = 0 → 4a + b = 0
Solving these we get
► a = -1.5
► b = 6
► c = 4.
So, f(x) = -1.5x2 + 6x + 4
at x = 5 gives -3.5.
DIRECTIONSfor the question:Solve the following question and mark the b...
Given:
- A quadratic function f(x) attains a maximum of 10 at x = 2.
- The value of the function at x = 0 is 4.
To Find:
- The value of f(x) at x = 5.
Solution:
To find the value of f(x) at x = 5, we need to determine the equation of the quadratic function f(x).
Step 1: Finding the equation of the quadratic function
Since the quadratic function attains a maximum at x = 2, we know that the vertex of the parabola lies at (2, 10). The vertex form of a quadratic function is given by:
f(x) = a(x - h)^2 + k
where (h, k) represents the vertex of the parabola.
Substituting the values of the vertex (2, 10) into the equation, we have:
f(x) = a(x - 2)^2 + 10
To find the value of 'a', we can use the fact that the value of the function at x = 0 is 4. Substituting these values into the equation, we have:
4 = a(0 - 2)^2 + 10
4 = 4a + 10
-6 = 4a
a = -6/4
a = -3/2
Therefore, the equation of the quadratic function is:
f(x) = (-3/2)(x - 2)^2 + 10
Step 2: Finding the value of f(x) at x = 5
To find the value of f(x) at x = 5, we substitute x = 5 into the equation:
f(5) = (-3/2)(5 - 2)^2 + 10
Simplifying the expression:
f(5) = (-3/2)(3)^2 + 10
f(5) = (-3/2)(9) + 10
f(5) = -27/2 + 10
f(5) = -27/2 + 20/2
f(5) = -7/2
Answer:
The value of f(x) at x = 5 is -7/2, which is equivalent to -3.5. Therefore, the correct answer is option A, -3.5.