Mechanical Engineering Exam > Mechanical Engineering Questions > A bar produces a lateral strain of magnitude...
Start Learning for Free
A bar produces a lateral strain of magnitude 60 x 10−5 when subjected to a tensile stress of magnitude 300 MPa along the axial direction. The elastic modulus of the material if the Poisson’s ratio is 0.3 is
- a)200 GPa
- b)150 GPa
- c)125 GPa
- d)100 GPa
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A bar produces a lateral strain of magnitude 60 x 10−5 when subjected...
Lateral strain = Axial strain x poisson′ s ratio ∈y=∈x x μ
= 150 GPa
This question is part of UPSC exam. View all Mechanical Engineering courses
Most Upvoted Answer
A bar produces a lateral strain of magnitude 60 x 10−5 when subjected...
Given:
- Lateral strain (ε) = 60 x 10^(-5)
- Tensile stress (σ) = 300 MPa
- Poisson's ratio (ν) = 0.3
To find:
Elastic modulus (E)
Formula:
Poisson's ratio is defined as the ratio of lateral strain to axial strain.
ν = -ε_lat / ε_axial
Elastic modulus is defined as the ratio of stress to strain.
E = σ / ε_axial
Solution:
Step 1: Calculate the axial strain (ε_axial) using Poisson's ratio and lateral strain.
ε_axial = -ε_lat / ν
ε_axial = -60 x 10^(-5) / 0.3
ε_axial = -2 x 10^(-4)
Step 2: Calculate the elastic modulus (E) using stress and axial strain.
E = σ / ε_axial
E = 300 x 10^6 / (-2 x 10^(-4))
E = -1500 x 10^9
E = 150 GPa
Answer:
The elastic modulus of the material, when the Poisson's ratio is 0.3, is 150 GPa. Therefore, the correct answer is option B.
- Lateral strain (ε) = 60 x 10^(-5)
- Tensile stress (σ) = 300 MPa
- Poisson's ratio (ν) = 0.3
To find:
Elastic modulus (E)
Formula:
Poisson's ratio is defined as the ratio of lateral strain to axial strain.
ν = -ε_lat / ε_axial
Elastic modulus is defined as the ratio of stress to strain.
E = σ / ε_axial
Solution:
Step 1: Calculate the axial strain (ε_axial) using Poisson's ratio and lateral strain.
ε_axial = -ε_lat / ν
ε_axial = -60 x 10^(-5) / 0.3
ε_axial = -2 x 10^(-4)
Step 2: Calculate the elastic modulus (E) using stress and axial strain.
E = σ / ε_axial
E = 300 x 10^6 / (-2 x 10^(-4))
E = -1500 x 10^9
E = 150 GPa
Answer:
The elastic modulus of the material, when the Poisson's ratio is 0.3, is 150 GPa. Therefore, the correct answer is option B.
Attention Mechanical Engineering Students!
To make sure you are not studying endlessly, EduRev has designed Mechanical Engineering study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Mechanical Engineering.
|
|
Explore Courses for Mechanical Engineering exam
|
|
Similar Mechanical Engineering Doubts
Top Courses for Mechanical EngineeringView all
A bar produces a lateral strain of magnitude 60 x 10−5 when subjected to a tensile stress of magnitude 300 MPa along the axial direction. The elastic modulus of the material if the Poisson’s ratio is 0.3 isa) 200 GPab) 150 GPac) 125 GPad) 100 GPaCorrect answer is option 'B'. Can you explain this answer?
Question Description
A bar produces a lateral strain of magnitude 60 x 10−5 when subjected to a tensile stress of magnitude 300 MPa along the axial direction. The elastic modulus of the material if the Poisson’s ratio is 0.3 isa) 200 GPab) 150 GPac) 125 GPad) 100 GPaCorrect answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A bar produces a lateral strain of magnitude 60 x 10−5 when subjected to a tensile stress of magnitude 300 MPa along the axial direction. The elastic modulus of the material if the Poisson’s ratio is 0.3 isa) 200 GPab) 150 GPac) 125 GPad) 100 GPaCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bar produces a lateral strain of magnitude 60 x 10−5 when subjected to a tensile stress of magnitude 300 MPa along the axial direction. The elastic modulus of the material if the Poisson’s ratio is 0.3 isa) 200 GPab) 150 GPac) 125 GPad) 100 GPaCorrect answer is option 'B'. Can you explain this answer?.
A bar produces a lateral strain of magnitude 60 x 10−5 when subjected to a tensile stress of magnitude 300 MPa along the axial direction. The elastic modulus of the material if the Poisson’s ratio is 0.3 isa) 200 GPab) 150 GPac) 125 GPad) 100 GPaCorrect answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A bar produces a lateral strain of magnitude 60 x 10−5 when subjected to a tensile stress of magnitude 300 MPa along the axial direction. The elastic modulus of the material if the Poisson’s ratio is 0.3 isa) 200 GPab) 150 GPac) 125 GPad) 100 GPaCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bar produces a lateral strain of magnitude 60 x 10−5 when subjected to a tensile stress of magnitude 300 MPa along the axial direction. The elastic modulus of the material if the Poisson’s ratio is 0.3 isa) 200 GPab) 150 GPac) 125 GPad) 100 GPaCorrect answer is option 'B'. Can you explain this answer?.
Solutions for A bar produces a lateral strain of magnitude 60 x 10−5 when subjected to a tensile stress of magnitude 300 MPa along the axial direction. The elastic modulus of the material if the Poisson’s ratio is 0.3 isa) 200 GPab) 150 GPac) 125 GPad) 100 GPaCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.
Here you can find the meaning of A bar produces a lateral strain of magnitude 60 x 10−5 when subjected to a tensile stress of magnitude 300 MPa along the axial direction. The elastic modulus of the material if the Poisson’s ratio is 0.3 isa) 200 GPab) 150 GPac) 125 GPad) 100 GPaCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A bar produces a lateral strain of magnitude 60 x 10−5 when subjected to a tensile stress of magnitude 300 MPa along the axial direction. The elastic modulus of the material if the Poisson’s ratio is 0.3 isa) 200 GPab) 150 GPac) 125 GPad) 100 GPaCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A bar produces a lateral strain of magnitude 60 x 10−5 when subjected to a tensile stress of magnitude 300 MPa along the axial direction. The elastic modulus of the material if the Poisson’s ratio is 0.3 isa) 200 GPab) 150 GPac) 125 GPad) 100 GPaCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A bar produces a lateral strain of magnitude 60 x 10−5 when subjected to a tensile stress of magnitude 300 MPa along the axial direction. The elastic modulus of the material if the Poisson’s ratio is 0.3 isa) 200 GPab) 150 GPac) 125 GPad) 100 GPaCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A bar produces a lateral strain of magnitude 60 x 10−5 when subjected to a tensile stress of magnitude 300 MPa along the axial direction. The elastic modulus of the material if the Poisson’s ratio is 0.3 isa) 200 GPab) 150 GPac) 125 GPad) 100 GPaCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
|
|
Explore Courses for Mechanical Engineering exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup