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If a piece of material neither expands or contracts in volume when subjected to stresses, then the Poission’s ratio must be
- a)zero
- b)0.25
- c)0.33
- d)0.5
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
If a piece of material neither expands or contracts in volume when su...
Volumetric strain
Material neither expands nor contracts in volume, so
εv = 0
1 − 2μ = 0
μ = 0.5
This question is part of UPSC exam. View all Mechanical Engineering courses
Most Upvoted Answer
If a piece of material neither expands or contracts in volume when su...
Explanation:
The Poisson's ratio is the ratio of lateral strain to longitudinal strain when a material is subjected to longitudinal stress. It is denoted by the symbol ν (nu). The formula for Poisson's ratio is:
ν = -lateral strain/longitudinal strain
When a material neither expands nor contracts in volume when subjected to stresses, it means that the lateral strain is equal to zero. Therefore, the Poisson's ratio can be calculated by the formula:
ν = 0/longitudinal strain
Since ν = 0 in this case, the longitudinal strain must also be zero. This is only possible if the material does not deform at all when subjected to stress along its longitudinal axis. Therefore, the material must be perfectly rigid.
The Poisson's ratio of a perfectly rigid material is defined as 0.5. This is because the lateral strain is always equal to half of the longitudinal strain for a perfectly rigid material.
Therefore, the correct answer to the question is option D, i.e., 0.5.
The Poisson's ratio is the ratio of lateral strain to longitudinal strain when a material is subjected to longitudinal stress. It is denoted by the symbol ν (nu). The formula for Poisson's ratio is:
ν = -lateral strain/longitudinal strain
When a material neither expands nor contracts in volume when subjected to stresses, it means that the lateral strain is equal to zero. Therefore, the Poisson's ratio can be calculated by the formula:
ν = 0/longitudinal strain
Since ν = 0 in this case, the longitudinal strain must also be zero. This is only possible if the material does not deform at all when subjected to stress along its longitudinal axis. Therefore, the material must be perfectly rigid.
The Poisson's ratio of a perfectly rigid material is defined as 0.5. This is because the lateral strain is always equal to half of the longitudinal strain for a perfectly rigid material.
Therefore, the correct answer to the question is option D, i.e., 0.5.
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If a piece of material neither expands or contracts in volume when subjected to stresses, then the Poission’s ratio must bea) zerob) 0.25c) 0.33d) 0.5Correct answer is option 'D'. Can you explain this answer?
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If a piece of material neither expands or contracts in volume when subjected to stresses, then the Poission’s ratio must bea) zerob) 0.25c) 0.33d) 0.5Correct answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about If a piece of material neither expands or contracts in volume when subjected to stresses, then the Poission’s ratio must bea) zerob) 0.25c) 0.33d) 0.5Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If a piece of material neither expands or contracts in volume when subjected to stresses, then the Poission’s ratio must bea) zerob) 0.25c) 0.33d) 0.5Correct answer is option 'D'. Can you explain this answer?.
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