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A tensile specimen with 12 mm initial diameter and 50 mm initial length is subjected to a load of 90 kN. After sometime, the diameter is 10mm. Assuming it as in compressible material, calculate true strain along the length. (Give answer upto 3 decimal places)
- a)0.364
- b)0.464
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A tensile specimen with 12 mm initial diameter and 50 mm initial lengt...
As, it is incompressible, volume = constant Hence, D02L0 = D12L1
View all questions of this test
Now, e =
= 
= 2 ln(1.2)
= 0.364
Question_Type: 5
Most Upvoted Answer
A tensile specimen with 12 mm initial diameter and 50 mm initial lengt...
To calculate the true strain along the length of the tensile specimen, we need to use the formula for true strain:
True strain (ε) = ln(Lf / Li)
where Lf is the final length of the specimen and Li is the initial length of the specimen.
In this problem, the initial length of the specimen is given as 50 mm, and we need to find the final length of the specimen.
We can use the concept of Poisson's ratio to find the final length. Poisson's ratio (ν) is the ratio of lateral strain to the axial strain. For an incompressible material, Poisson's ratio is 0.5.
Using the formula for Poisson's ratio:
ν = Δd / d
where Δd is the change in diameter and d is the initial diameter.
In this problem, the initial diameter is given as 12 mm, and the change in diameter is given as 12 mm - 10 mm = 2 mm.
Substituting the values into the formula:
0.5 = 2 mm / 12 mm
Simplifying the equation, we find the initial diameter is 6 times the change in diameter.
Now, we can find the final length of the specimen:
Lf = Li * (d / (d - Δd))
Substituting the values into the formula:
Lf = 50 mm * (12 mm / (12 mm - 2 mm))
= 50 mm * (12 mm / 10 mm)
= 60 mm
Now, we can substitute the values of Lf and Li into the formula for true strain:
ε = ln(60 mm / 50 mm)
= ln(1.2)
≈ 0.182
Therefore, the true strain along the length of the tensile specimen is approximately 0.182.
True strain (ε) = ln(Lf / Li)
where Lf is the final length of the specimen and Li is the initial length of the specimen.
In this problem, the initial length of the specimen is given as 50 mm, and we need to find the final length of the specimen.
We can use the concept of Poisson's ratio to find the final length. Poisson's ratio (ν) is the ratio of lateral strain to the axial strain. For an incompressible material, Poisson's ratio is 0.5.
Using the formula for Poisson's ratio:
ν = Δd / d
where Δd is the change in diameter and d is the initial diameter.
In this problem, the initial diameter is given as 12 mm, and the change in diameter is given as 12 mm - 10 mm = 2 mm.
Substituting the values into the formula:
0.5 = 2 mm / 12 mm
Simplifying the equation, we find the initial diameter is 6 times the change in diameter.
Now, we can find the final length of the specimen:
Lf = Li * (d / (d - Δd))
Substituting the values into the formula:
Lf = 50 mm * (12 mm / (12 mm - 2 mm))
= 50 mm * (12 mm / 10 mm)
= 60 mm
Now, we can substitute the values of Lf and Li into the formula for true strain:
ε = ln(60 mm / 50 mm)
= ln(1.2)
≈ 0.182
Therefore, the true strain along the length of the tensile specimen is approximately 0.182.
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A tensile specimen with 12 mm initial diameter and 50 mm initial length is subjected to a load of 90 kN. After sometime, the diameter is 10mm. Assuming it as in compressible material, calculate true strain along the length. (Give answer upto 3 decimal places)a)0.364b)0.464Correct answer is option 'A'. Can you explain this answer?
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A tensile specimen with 12 mm initial diameter and 50 mm initial length is subjected to a load of 90 kN. After sometime, the diameter is 10mm. Assuming it as in compressible material, calculate true strain along the length. (Give answer upto 3 decimal places)a)0.364b)0.464Correct answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A tensile specimen with 12 mm initial diameter and 50 mm initial length is subjected to a load of 90 kN. After sometime, the diameter is 10mm. Assuming it as in compressible material, calculate true strain along the length. (Give answer upto 3 decimal places)a)0.364b)0.464Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A tensile specimen with 12 mm initial diameter and 50 mm initial length is subjected to a load of 90 kN. After sometime, the diameter is 10mm. Assuming it as in compressible material, calculate true strain along the length. (Give answer upto 3 decimal places)a)0.364b)0.464Correct answer is option 'A'. Can you explain this answer?.
A tensile specimen with 12 mm initial diameter and 50 mm initial length is subjected to a load of 90 kN. After sometime, the diameter is 10mm. Assuming it as in compressible material, calculate true strain along the length. (Give answer upto 3 decimal places)a)0.364b)0.464Correct answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A tensile specimen with 12 mm initial diameter and 50 mm initial length is subjected to a load of 90 kN. After sometime, the diameter is 10mm. Assuming it as in compressible material, calculate true strain along the length. (Give answer upto 3 decimal places)a)0.364b)0.464Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A tensile specimen with 12 mm initial diameter and 50 mm initial length is subjected to a load of 90 kN. After sometime, the diameter is 10mm. Assuming it as in compressible material, calculate true strain along the length. (Give answer upto 3 decimal places)a)0.364b)0.464Correct answer is option 'A'. Can you explain this answer?.
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A tensile specimen with 12 mm initial diameter and 50 mm initial length is subjected to a load of 90 kN. After sometime, the diameter is 10mm. Assuming it as in compressible material, calculate true strain along the length. (Give answer upto 3 decimal places)a)0.364b)0.464Correct answer is option 'A'. Can you explain this answer?, a detailed solution for A tensile specimen with 12 mm initial diameter and 50 mm initial length is subjected to a load of 90 kN. After sometime, the diameter is 10mm. Assuming it as in compressible material, calculate true strain along the length. (Give answer upto 3 decimal places)a)0.364b)0.464Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of A tensile specimen with 12 mm initial diameter and 50 mm initial length is subjected to a load of 90 kN. After sometime, the diameter is 10mm. Assuming it as in compressible material, calculate true strain along the length. (Give answer upto 3 decimal places)a)0.364b)0.464Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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