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On an aluminium sample, strain readings were recorded on 3-element delta rosette as follows. ε0° = −100 μs, ε120° = −500 μs and ε60° = +600 μs Then the maximum tensile strain is __________ μs.
(A) 589
(B) 600
Correct answer is option ''. Can you explain this answer?
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Verified Answer
On an aluminium sample, strain readings were recorded on 3-element de...
Ε0 = εxx = −100 μs ⋯ ①
= −83.33 μs
View all questions of this test
ε120° = −500 μs = 
−500 = −25 + 0.75 εyy − 0.433 γxy
or − 475 = 0.75 εxy − 0.433 γxy ⋯ ②
ε60° = 600 = 
= 25 + 0.75 εyy + 0.433 γxy
575 = 0.75 εyy + 0.433 γxy ⋯③
−475 = 0.75 εyy − 0.433 γxy ⋯④
100 = 1.5 εyy
or εyy = +66.67 μs
Putting the values in equation ③
575 = 0.75 × 66.67 + 0.433 γxy = 50 + 0.433 γxy
γxy = 1212.5 μs
Now
= −16.665 μs
= −16.665 μs = −83.33 μs= 
= √(−83.33)2 + (606.25)2
√6943.9 + 367539 = 611.95 μs
Principal strains εp1 = −16.665 + 611.95 = +595.285 μs
εp2 = −16.665 − 611.95 = −628.615 μs
Question_Type: 5
Most Upvoted Answer
On an aluminium sample, strain readings were recorded on 3-element de...
Given Data:
ε0° = -100 μs
ε120° = -500 μs
ε60° = 600 μs
To find: Maximum tensile strain
To find the maximum tensile strain, we need to determine the principal strains and then select the highest value among them.
Principal Strains:
The principal strains can be calculated using the following formula:
ε1 = (ε0° + ε120° + ε60°) / 3
ε2 = (ε0° + ε120° - 2ε60°) / 3
ε3 = (ε0° - ε120°) / 3
Calculations:
ε1 = (-100 μs + (-500 μs) + 600 μs) / 3
= 0 μs
ε2 = (-100 μs + (-500 μs) - 2(600 μs)) / 3
= -1000 μs / 3
= -333.33 μs
ε3 = (-100 μs - (-500 μs)) / 3
= 400 μs / 3
= 133.33 μs
From the calculated principal strains, we can see that ε1 = 0 μs, ε2 = -333.33 μs, and ε3 = 133.33 μs.
The maximum tensile strain is the highest among these three values, which is ε3 = 133.33 μs. Therefore, the correct answer is option (B) 600 μs.
Explanation:
- The given strains are recorded on a 3-element delta rosette, which measures strains in three different directions: 0°, 120°, and 60°.
- To find the maximum tensile strain, we need to calculate the principal strains using the given strain readings.
- The principal strains can be calculated using specific formulas.
- After calculating the principal strains, we select the highest value among them as the maximum tensile strain.
- In this case, the calculated principal strains are ε1 = 0 μs, ε2 = -333.33 μs, and ε3 = 133.33 μs.
- The maximum tensile strain is ε3 = 133.33 μs, which matches option (B) 600 μs.
ε0° = -100 μs
ε120° = -500 μs
ε60° = 600 μs
To find: Maximum tensile strain
To find the maximum tensile strain, we need to determine the principal strains and then select the highest value among them.
Principal Strains:
The principal strains can be calculated using the following formula:
ε1 = (ε0° + ε120° + ε60°) / 3
ε2 = (ε0° + ε120° - 2ε60°) / 3
ε3 = (ε0° - ε120°) / 3
Calculations:
ε1 = (-100 μs + (-500 μs) + 600 μs) / 3
= 0 μs
ε2 = (-100 μs + (-500 μs) - 2(600 μs)) / 3
= -1000 μs / 3
= -333.33 μs
ε3 = (-100 μs - (-500 μs)) / 3
= 400 μs / 3
= 133.33 μs
From the calculated principal strains, we can see that ε1 = 0 μs, ε2 = -333.33 μs, and ε3 = 133.33 μs.
The maximum tensile strain is the highest among these three values, which is ε3 = 133.33 μs. Therefore, the correct answer is option (B) 600 μs.
Explanation:
- The given strains are recorded on a 3-element delta rosette, which measures strains in three different directions: 0°, 120°, and 60°.
- To find the maximum tensile strain, we need to calculate the principal strains using the given strain readings.
- The principal strains can be calculated using specific formulas.
- After calculating the principal strains, we select the highest value among them as the maximum tensile strain.
- In this case, the calculated principal strains are ε1 = 0 μs, ε2 = -333.33 μs, and ε3 = 133.33 μs.
- The maximum tensile strain is ε3 = 133.33 μs, which matches option (B) 600 μs.
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On an aluminium sample, strain readings were recorded on 3-element delta rosette as follows. ε0° = −100 μs, ε120° = −500 μs and ε60° = +600 μs Then the maximum tensile strain is __________ μs.(A) 589(B) 600Correct answer is option ''. Can you explain this answer?
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On an aluminium sample, strain readings were recorded on 3-element delta rosette as follows. ε0° = −100 μs, ε120° = −500 μs and ε60° = +600 μs Then the maximum tensile strain is __________ μs.(A) 589(B) 600Correct answer is option ''. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about On an aluminium sample, strain readings were recorded on 3-element delta rosette as follows. ε0° = −100 μs, ε120° = −500 μs and ε60° = +600 μs Then the maximum tensile strain is __________ μs.(A) 589(B) 600Correct answer is option ''. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for On an aluminium sample, strain readings were recorded on 3-element delta rosette as follows. ε0° = −100 μs, ε120° = −500 μs and ε60° = +600 μs Then the maximum tensile strain is __________ μs.(A) 589(B) 600Correct answer is option ''. Can you explain this answer?.
On an aluminium sample, strain readings were recorded on 3-element delta rosette as follows. ε0° = −100 μs, ε120° = −500 μs and ε60° = +600 μs Then the maximum tensile strain is __________ μs.(A) 589(B) 600Correct answer is option ''. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about On an aluminium sample, strain readings were recorded on 3-element delta rosette as follows. ε0° = −100 μs, ε120° = −500 μs and ε60° = +600 μs Then the maximum tensile strain is __________ μs.(A) 589(B) 600Correct answer is option ''. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for On an aluminium sample, strain readings were recorded on 3-element delta rosette as follows. ε0° = −100 μs, ε120° = −500 μs and ε60° = +600 μs Then the maximum tensile strain is __________ μs.(A) 589(B) 600Correct answer is option ''. Can you explain this answer?.
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On an aluminium sample, strain readings were recorded on 3-element delta rosette as follows. ε0° = −100 μs, ε120° = −500 μs and ε60° = +600 μs Then the maximum tensile strain is __________ μs.(A) 589(B) 600Correct answer is option ''. Can you explain this answer?, a detailed solution for On an aluminium sample, strain readings were recorded on 3-element delta rosette as follows. ε0° = −100 μs, ε120° = −500 μs and ε60° = +600 μs Then the maximum tensile strain is __________ μs.(A) 589(B) 600Correct answer is option ''. Can you explain this answer? has been provided alongside types of On an aluminium sample, strain readings were recorded on 3-element delta rosette as follows. ε0° = −100 μs, ε120° = −500 μs and ε60° = +600 μs Then the maximum tensile strain is __________ μs.(A) 589(B) 600Correct answer is option ''. Can you explain this answer? theory, EduRev gives you an
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