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The data obtained from a rectangular strain gage rosette attached to a stressed steel member are ε0 = −220 × 10−6, ε45° = 120 × 10−6, ε90° = +220 × 10−6.Given E = 2 × 105 N⁄mm2 and Poisson’s ratio = 0.3. The principal stress acting at the point is ___________ MPa(A) 37.5(B) 39.5Correct answer is option ''. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The data obtained from a rectangular strain gage rosette attached to a stressed steel member are ε0 = −220 × 10−6, ε45° = 120 × 10−6, ε90° = +220 × 10−6.Given E = 2 × 105 N⁄mm2 and Poisson’s ratio = 0.3. The principal stress acting at the point is ___________ MPa(A) 37.5(B) 39.5Correct answer is option ''. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The data obtained from a rectangular strain gage rosette attached to a stressed steel member are ε0 = −220 × 10−6, ε45° = 120 × 10−6, ε90° = +220 × 10−6.Given E = 2 × 105 N⁄mm2 and Poisson’s ratio = 0.3. The principal stress acting at the point is ___________ MPa(A) 37.5(B) 39.5Correct answer is option ''. Can you explain this answer?.

Solutions for The data obtained from a rectangular strain gage rosette attached to a stressed steel member are ε0 = −220 × 10−6, ε45° = 120 × 10−6, ε90° = +220 × 10−6.Given E = 2 × 105 N⁄mm2 and Poisson’s ratio = 0.3. The principal stress acting at the point is ___________ MPa(A) 37.5(B) 39.5Correct answer is option ''. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.

Here you can find the meaning of The data obtained from a rectangular strain gage rosette attached to a stressed steel member are ε0 = −220 × 10−6, ε45° = 120 × 10−6, ε90° = +220 × 10−6.Given E = 2 × 105 N⁄mm2 and Poisson’s ratio = 0.3. The principal stress acting at the point is ___________ MPa(A) 37.5(B) 39.5Correct answer is option ''. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The data obtained from a rectangular strain gage rosette attached to a stressed steel member are ε0 = −220 × 10−6, ε45° = 120 × 10−6, ε90° = +220 × 10−6.Given E = 2 × 105 N⁄mm2 and Poisson’s ratio = 0.3. The principal stress acting at the point is ___________ MPa(A) 37.5(B) 39.5Correct answer is option ''. Can you explain this answer?, a detailed solution for The data obtained from a rectangular strain gage rosette attached to a stressed steel member are ε0 = −220 × 10−6, ε45° = 120 × 10−6, ε90° = +220 × 10−6.Given E = 2 × 105 N⁄mm2 and Poisson’s ratio = 0.3. The principal stress acting at the point is ___________ MPa(A) 37.5(B) 39.5Correct answer is option ''. Can you explain this answer? has been provided alongside types of The data obtained from a rectangular strain gage rosette attached to a stressed steel member are ε0 = −220 × 10−6, ε45° = 120 × 10−6, ε90° = +220 × 10−6.Given E = 2 × 105 N⁄mm2 and Poisson’s ratio = 0.3. The principal stress acting at the point is ___________ MPa(A) 37.5(B) 39.5Correct answer is option ''. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The data obtained from a rectangular strain gage rosette attached to a stressed steel member are ε0 = −220 × 10−6, ε45° = 120 × 10−6, ε90° = +220 × 10−6.Given E = 2 × 105 N⁄mm2 and Poisson’s ratio = 0.3. The principal stress acting at the point is ___________ MPa(A) 37.5(B) 39.5Correct answer is option ''. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.