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4y(3y2 5y-7) and 2(y3-4y2 5. Answer this?
Most Upvoted Answer
4y(3y2 5y-7) and 2(y3-4y2 5. Answer this?
= 4y(3y² + 5y - 7) + 2( y³ - 4y² + 5)
= 12y³ + 20y - 28y +2 (y³ - 4y² + 5)
= 12y³ + 20y² - 28y + 2 ( y³ - 4y² + 5)
= 12y³ +20y² - 28y + 2y³ -8y² +10
= 14y³ + 20y² - 28y - 8y² +10
= 14y³ + 20y² - 28y - 8y² +10
= 14y³ + 12y² - 28y + 10

Answer:

= 14y³ + 12y² - 28y + 10
Community Answer
4y(3y2 5y-7) and 2(y3-4y2 5. Answer this?




Solution:





Distributing the terms:


  • First, distribute the term 4y to each term inside the parentheses of the first expression:


    • 4y * 3y^2 = 12y^3

    • 4y * 5y = 20y^2

    • 4y * -7 = -28y




Simplifying the first expression:


  • After distributing the terms, the first expression becomes: 12y^3 + 20y^2 - 28y



Distributing the terms:


  • Next, distribute the term 2y to each term inside the parentheses of the second expression:


    • 2y * y^3 = 2y^4

    • 2y * -4y^2 = -8y^3

    • 2y * 5 = 10y




Simplifying the second expression:


  • After distributing the terms, the second expression becomes: 2y^4 - 8y^3 + 10y



Final answer after simplifying both expressions:


  • Combining the simplified expressions, we get: 12y^3 + 20y^2 - 28y + 2y^4 - 8y^3 + 10y

  • Therefore, the final simplified expression is: 2y^4 + 4y^3 + 20y^2 - 18y




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4y(3y2 5y-7) and 2(y3-4y2 5. Answer this?
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