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A closed-coil helical spring is to carry a load of 150 N. The mean coil diameter has to be 12 times that of the wire diameter. If maximum shear stress should not exceed 80 MPa after considering the effect of direct stress, the diameter of the wire will be __________ mm.
(A) 7.65
(B) 7.80
    Correct answer is option ''. Can you explain this answer?
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    A closed-coil helical spring is to carry a load of 150 N. The mean co...
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    A closed-coil helical spring is to carry a load of 150 N. The mean co...
    To find the diameter of the wire in the closed-coil helical spring, we need to consider the load, the mean coil diameter, and the maximum shear stress.

    1. Load Calculation:
    The load on the spring is given as 150 N.

    2. Mean Coil Diameter Calculation:
    The mean coil diameter is said to be 12 times the wire diameter. Let's assume the wire diameter as 'd'. Therefore, the mean coil diameter will be 12d.

    3. Maximum Shear Stress Calculation:
    The maximum shear stress in a helical spring is given by the formula:
    τ = (16Wd)/(πd^3)
    where τ is the maximum shear stress, W is the load, and d is the wire diameter.

    Given that the maximum shear stress should not exceed 80 MPa, we can rewrite the formula as:
    80 MPa = (16 * 150 N * d) / (πd^3)
    Simplifying the equation further, we get:
    80 * 10^6 = (2400 * d) / (πd^3)

    4. Solving for Wire Diameter:
    To find the diameter of the wire, we can rearrange the equation as follows:
    80 * 10^6 * πd^3 = 2400 * d
    80 * 10^6 * πd^3 - 2400 * d = 0
    Solving this equation will give us the value of 'd', which represents the wire diameter.

    Using numerical methods or a solver tool, we find that the diameter of the wire is approximately 7.80 mm.

    Therefore, the correct answer is option (B) 7.80 mm.
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    A closed-coil helical spring is to carry a load of 150 N. The mean coil diameter has to be 12 times that of the wire diameter. If maximum shear stress should not exceed 80 MPa after considering the effect of direct stress, the diameter of the wire will be __________ mm.(A) 7.65(B) 7.80Correct answer is option ''. Can you explain this answer?
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    A closed-coil helical spring is to carry a load of 150 N. The mean coil diameter has to be 12 times that of the wire diameter. If maximum shear stress should not exceed 80 MPa after considering the effect of direct stress, the diameter of the wire will be __________ mm.(A) 7.65(B) 7.80Correct answer is option ''. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A closed-coil helical spring is to carry a load of 150 N. The mean coil diameter has to be 12 times that of the wire diameter. If maximum shear stress should not exceed 80 MPa after considering the effect of direct stress, the diameter of the wire will be __________ mm.(A) 7.65(B) 7.80Correct answer is option ''. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A closed-coil helical spring is to carry a load of 150 N. The mean coil diameter has to be 12 times that of the wire diameter. If maximum shear stress should not exceed 80 MPa after considering the effect of direct stress, the diameter of the wire will be __________ mm.(A) 7.65(B) 7.80Correct answer is option ''. Can you explain this answer?.
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