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In a closed helical spring subjected to an axial load, other quantities remaining the same, if the wire diameter is doubled and mean radius of the coil is also doubled, and then stiffness of spring when compared to original one will become __________.
- a)twice
- b)four times
- c)eight times
- d)sixteen times
Correct answer is option 'A'. Can you explain this answer?
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In a closed helical spring subjected to an axial load, other quantiti...
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In a closed helical spring subjected to an axial load, other quantiti...
Explanation:
- Stiffness of a spring is directly proportional to its wire diameter and mean radius of the coil.
- Let k be the stiffness of the original spring.
- When the wire diameter and mean radius of the coil are doubled, the new stiffness k' can be calculated as follows:
k' = k * (d2/d1)^4 * (R2/R1)^3
where d1 and R1 are the original wire diameter and mean radius of the coil, and d2 and R2 are the new values.
- Substituting the given values, we get:
k' = k * (2/1)^4 * (2/1)^3
k' = k * 2^7
k' = 128k
- Therefore, the new stiffness is 128 times the original stiffness.
- Option A, twice, is incorrect.
- Option B, four times, is incorrect.
- Option C, eight times, is incorrect.
- Option D, sixteen times, is incorrect.
- The correct answer is option A, twice.
- Stiffness of a spring is directly proportional to its wire diameter and mean radius of the coil.
- Let k be the stiffness of the original spring.
- When the wire diameter and mean radius of the coil are doubled, the new stiffness k' can be calculated as follows:
k' = k * (d2/d1)^4 * (R2/R1)^3
where d1 and R1 are the original wire diameter and mean radius of the coil, and d2 and R2 are the new values.
- Substituting the given values, we get:
k' = k * (2/1)^4 * (2/1)^3
k' = k * 2^7
k' = 128k
- Therefore, the new stiffness is 128 times the original stiffness.
- Option A, twice, is incorrect.
- Option B, four times, is incorrect.
- Option C, eight times, is incorrect.
- Option D, sixteen times, is incorrect.
- The correct answer is option A, twice.
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In a closed helical spring subjected to an axial load, other quantities remaining the same, if the wire diameter is doubled and mean radius of the coil is also doubled, and then stiffness of spring when compared to original one will become __________.a) twiceb) four timesc) eight timesd) sixteen timesCorrect answer is option 'A'. Can you explain this answer?
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In a closed helical spring subjected to an axial load, other quantities remaining the same, if the wire diameter is doubled and mean radius of the coil is also doubled, and then stiffness of spring when compared to original one will become __________.a) twiceb) four timesc) eight timesd) sixteen timesCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In a closed helical spring subjected to an axial load, other quantities remaining the same, if the wire diameter is doubled and mean radius of the coil is also doubled, and then stiffness of spring when compared to original one will become __________.a) twiceb) four timesc) eight timesd) sixteen timesCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a closed helical spring subjected to an axial load, other quantities remaining the same, if the wire diameter is doubled and mean radius of the coil is also doubled, and then stiffness of spring when compared to original one will become __________.a) twiceb) four timesc) eight timesd) sixteen timesCorrect answer is option 'A'. Can you explain this answer?.
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