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Rate constant k varies with temperature by equation log10k(min-1) = 5 2000/T. We can concludea)Pre exponential factor A is 105b)Eais 2000 k calc)Eais 9.212 k cald)Pre exponential factor A is 5Correct answer is option 'A,C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Rate constant k varies with temperature by equation log10k(min-1) = 5 2000/T. We can concludea)Pre exponential factor A is 105b)Eais 2000 k calc)Eais 9.212 k cald)Pre exponential factor A is 5Correct answer is option 'A,C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Rate constant k varies with temperature by equation log10k(min-1) = 5 2000/T. We can concludea)Pre exponential factor A is 105b)Eais 2000 k calc)Eais 9.212 k cald)Pre exponential factor A is 5Correct answer is option 'A,C'. Can you explain this answer?.

Solutions for Rate constant k varies with temperature by equation log10k(min-1) = 5 2000/T. We can concludea)Pre exponential factor A is 105b)Eais 2000 k calc)Eais 9.212 k cald)Pre exponential factor A is 5Correct answer is option 'A,C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

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