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The vapour pressure of ethanol and methanol are 44.5 mm and 88.7 mm Hg respectively. An ideal solution is prepared at the same temperature by mixing 60 g of ethanol with 40 g of methanol. Calculate total vapour pressure of the solution.
    Correct answer is '66.15'. Can you explain this answer?
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    Verified Answer
    The vapour pressure of ethanol and methanol are 44.5 mm and 88.7 mm Hg...


    P = 0.51 × 44.5 + 0.49 × 88.7
    = 66.15
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    Most Upvoted Answer
    The vapour pressure of ethanol and methanol are 44.5 mm and 88.7 mm Hg...
    Given:

    Vapour pressure of ethanol (PE) = 44.5 mm

    Vapour pressure of methanol (PM) = 88.7 mm

    Mass of ethanol (mE) = 60 g

    Mass of methanol (mM) = 40 g

    To find:

    Total vapour pressure of the solution

    Solution:

    Step 1: Calculate mole fraction of ethanol (XE) and methanol (XM) in the solution

    Moles of ethanol (nE) = mE/molecular weight of ethanol

    Moles of methanol (nM) = mM/molecular weight of methanol

    Molecular weight of ethanol (46 g/mol) and methanol (32 g/mol) are taken from periodic table

    nE = 60/46 = 1.304

    nM = 40/32 = 1.25

    Total moles of the solution (nT) = nE + nM = 1.304 + 1.25 = 2.554 mol

    XE = nE/nT = 1.304/2.554 = 0.51

    XM = nM/nT = 1.25/2.554 = 0.49


    Step 2: Calculate partial pressure of ethanol (PE*) and methanol (PM*) in the solution

    Using Raoult's law, PE* = XE x PE = 0.51 x 44.5 = 22.7 mm

    PM* = XM x PM = 0.49 x 88.7 = 43.4 mm


    Step 3: Calculate total vapour pressure of the solution

    Using Dalton's law of partial pressures, PT = PE* + PM* = 22.7 + 43.4 = 66.1 mm

    Answer:

    Total vapour pressure of the solution is 66.1 mm.
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    The vapour pressure of ethanol and methanol are 44.5 mm and 88.7 mm Hg respectively. An ideal solution is prepared at the same temperature by mixing 60 g of ethanol with 40 g of methanol. Calculate total vapour pressure of the solution.Correct answer is '66.15'. Can you explain this answer?
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    The vapour pressure of ethanol and methanol are 44.5 mm and 88.7 mm Hg respectively. An ideal solution is prepared at the same temperature by mixing 60 g of ethanol with 40 g of methanol. Calculate total vapour pressure of the solution.Correct answer is '66.15'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The vapour pressure of ethanol and methanol are 44.5 mm and 88.7 mm Hg respectively. An ideal solution is prepared at the same temperature by mixing 60 g of ethanol with 40 g of methanol. Calculate total vapour pressure of the solution.Correct answer is '66.15'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The vapour pressure of ethanol and methanol are 44.5 mm and 88.7 mm Hg respectively. An ideal solution is prepared at the same temperature by mixing 60 g of ethanol with 40 g of methanol. Calculate total vapour pressure of the solution.Correct answer is '66.15'. Can you explain this answer?.
    Solutions for The vapour pressure of ethanol and methanol are 44.5 mm and 88.7 mm Hg respectively. An ideal solution is prepared at the same temperature by mixing 60 g of ethanol with 40 g of methanol. Calculate total vapour pressure of the solution.Correct answer is '66.15'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
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