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In a counter-flow heat exchanger, water is heated at the rate of 1.5 kg/s from 40°C to 80°C by an oil entering at 120°C and leaving at 60°C. The specific heats of water and oil are 4.2 kJ/ kgK and 2 kJ/kgK, respectively. The overall heat transfer coefficient is 400 W/m2K.The required heat transfer surface area (in m2) is
[2007]
  • a)
    0.104
  • b)
    0.022
  • c)
    10.4
  • d)
    21.84
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
In a counter-flow heat exchanger, water is heated at the rate of 1.5 k...
Heat exchanger is a counterflow type.




= 21.83 m2.
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Most Upvoted Answer
In a counter-flow heat exchanger, water is heated at the rate of 1.5 k...
°C to 80°C by hot air flowing at a rate of 2 kg/s. The specific heat capacity of water is 4.18 kJ/kg°C. Calculate the heat transfer rate in the heat exchanger.

To calculate the heat transfer rate in the heat exchanger, we can use the formula:

Q = m * c * ΔT

Where:
Q = heat transfer rate (in kW)
m = mass flow rate (in kg/s)
c = specific heat capacity (in kJ/kg°C)
ΔT = change in temperature (in °C)

Given:
m_water = 1.5 kg/s (mass flow rate of water)
c_water = 4.18 kJ/kg°C (specific heat capacity of water)
ΔT_water = (80 - 40) °C = 40 °C (change in temperature of water)

m_air = 2 kg/s (mass flow rate of air)
c_air = ? (specific heat capacity of air)
ΔT_air = ? (change in temperature of air)

Since we know the mass flow rate and change in temperature of the water, we can calculate the heat transfer rate for water:

Q_water = m_water * c_water * ΔT_water

Q_water = 1.5 kg/s * 4.18 kJ/kg°C * 40°C
Q_water = 250.8 kJ/s = 250.8 kW

Next, we need to determine the change in temperature of the air. Since it is being heated, the change in temperature of the air will be the same as the change in temperature of the water:

ΔT_air = ΔT_water = 40 °C

Now, we can calculate the heat transfer rate for air using the same formula:

Q_air = m_air * c_air * ΔT_air

250.8 kW = 2 kg/s * c_air * 40°C
c_air = 250.8 kW / (2 kg/s * 40°C)
c_air = 3.135 kJ/kg°C

Therefore, the heat transfer rate in the counter-flow heat exchanger is 250.8 kW.
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In a counter-flow heat exchanger, water is heated at the rate of 1.5 kg/s from 40°C to 80°C by an oil entering at 120°C and leaving at 60°C. The specific heats of water and oil are 4.2 kJ/ kgK and 2 kJ/kgK, respectively. The overall heat transfer coefficient is 400 W/m2K.The required heat transfer surface area (in m2) is[2007]a)0.104b)0.022c)10.4d)21.84Correct answer is option 'D'. Can you explain this answer?
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