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Two pipes of inner diameter 100 mm and outer diameter 110 mm each are joined by flash butt welding using 30 V power supply. At the interface, 1 mm of material melts from each pipe which has a resistance of 42.4 ohms. If the unit melt energy is 64.4 MJ/m3, then time required for welding (in s) is
[ME 2010]
- a)1
- b)5
- c)10
- d)20
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Two pipes of inner diameter 100 mm and outer diameter 110 mm each are ...
Energy Required for melting/volume
E= 64.4 MJ/m3
V= 30 volts
R = 42.4 Ω
di = 100 mm
do = 110 mm
= 212.32 Joules
E= 64.4 MJ/m3
V= 30 volts
R = 42.4 Ω
di = 100 mm
do = 110 mm
= 212.32 Joules
Most Upvoted Answer
Two pipes of inner diameter 100 mm and outer diameter 110 mm each are ...
To find the time required for welding, we need to calculate the total energy required for melting the material at the interface of the two pipes. We can then use the power supply and resistance values to calculate the time.
1. Calculate the volume of material melted:
The volume of material melted can be calculated by finding the difference in volume between the inner and outer diameters of the pipes. Since 1 mm of material melts from each pipe, the difference in volume would be the same for both pipes.
Volume of material melted = π/4 * ((D_outer^2 - D_inner^2)/4) * L
Where D_outer = outer diameter of the pipe, D_inner = inner diameter of the pipe, and L = length of the interface
2. Calculate the energy required to melt the material:
The energy required to melt the material can be calculated using the unit melt energy and the volume of material melted.
Energy required = Unit melt energy * Volume of material melted
Energy required = 64.4 MJ/m^3 * Volume of material melted
3. Calculate the time required for welding:
The power supply provides a voltage of 30 V, and the resistance of the material at the interface is given as 42.4 ohms. We can use the power formula to calculate the power.
Power = (Voltage^2) / Resistance
Since we know the power and the energy required, we can use the formula:
Energy = Power * Time
We can rearrange the formula to solve for time:
Time = Energy / Power
Substituting the values, we get:
Time = (64.4 MJ/m^3 * Volume of material melted) / ((Voltage^2) / Resistance)
Simplifying further, we have:
Time = (64.4 MJ/m^3 * π/4 * ((D_outer^2 - D_inner^2)/4) * L) / ((30^2) / 42.4)
Now, substituting the given values:
D_outer = 110 mm = 0.11 m
D_inner = 100 mm = 0.1 m
L = length of the interface (not given)
We can substitute these values into the formula and calculate the time required for welding.
1. Calculate the volume of material melted:
The volume of material melted can be calculated by finding the difference in volume between the inner and outer diameters of the pipes. Since 1 mm of material melts from each pipe, the difference in volume would be the same for both pipes.
Volume of material melted = π/4 * ((D_outer^2 - D_inner^2)/4) * L
Where D_outer = outer diameter of the pipe, D_inner = inner diameter of the pipe, and L = length of the interface
2. Calculate the energy required to melt the material:
The energy required to melt the material can be calculated using the unit melt energy and the volume of material melted.
Energy required = Unit melt energy * Volume of material melted
Energy required = 64.4 MJ/m^3 * Volume of material melted
3. Calculate the time required for welding:
The power supply provides a voltage of 30 V, and the resistance of the material at the interface is given as 42.4 ohms. We can use the power formula to calculate the power.
Power = (Voltage^2) / Resistance
Since we know the power and the energy required, we can use the formula:
Energy = Power * Time
We can rearrange the formula to solve for time:
Time = Energy / Power
Substituting the values, we get:
Time = (64.4 MJ/m^3 * Volume of material melted) / ((Voltage^2) / Resistance)
Simplifying further, we have:
Time = (64.4 MJ/m^3 * π/4 * ((D_outer^2 - D_inner^2)/4) * L) / ((30^2) / 42.4)
Now, substituting the given values:
D_outer = 110 mm = 0.11 m
D_inner = 100 mm = 0.1 m
L = length of the interface (not given)
We can substitute these values into the formula and calculate the time required for welding.
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Two pipes of inner diameter 100 mm and outer diameter 110 mm each are joined by flash butt welding using 30 V power supply. At the interface, 1 mm of material melts from each pipe which has a resistance of 42.4 ohms. If the unit melt energy is 64.4 MJ/m3, then time required for welding (in s) is[ME 2010]a)1b)5c)10d)20Correct answer is option 'C'. Can you explain this answer?
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Two pipes of inner diameter 100 mm and outer diameter 110 mm each are joined by flash butt welding using 30 V power supply. At the interface, 1 mm of material melts from each pipe which has a resistance of 42.4 ohms. If the unit melt energy is 64.4 MJ/m3, then time required for welding (in s) is[ME 2010]a)1b)5c)10d)20Correct answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Two pipes of inner diameter 100 mm and outer diameter 110 mm each are joined by flash butt welding using 30 V power supply. At the interface, 1 mm of material melts from each pipe which has a resistance of 42.4 ohms. If the unit melt energy is 64.4 MJ/m3, then time required for welding (in s) is[ME 2010]a)1b)5c)10d)20Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two pipes of inner diameter 100 mm and outer diameter 110 mm each are joined by flash butt welding using 30 V power supply. At the interface, 1 mm of material melts from each pipe which has a resistance of 42.4 ohms. If the unit melt energy is 64.4 MJ/m3, then time required for welding (in s) is[ME 2010]a)1b)5c)10d)20Correct answer is option 'C'. Can you explain this answer?.
Two pipes of inner diameter 100 mm and outer diameter 110 mm each are joined by flash butt welding using 30 V power supply. At the interface, 1 mm of material melts from each pipe which has a resistance of 42.4 ohms. If the unit melt energy is 64.4 MJ/m3, then time required for welding (in s) is[ME 2010]a)1b)5c)10d)20Correct answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Two pipes of inner diameter 100 mm and outer diameter 110 mm each are joined by flash butt welding using 30 V power supply. At the interface, 1 mm of material melts from each pipe which has a resistance of 42.4 ohms. If the unit melt energy is 64.4 MJ/m3, then time required for welding (in s) is[ME 2010]a)1b)5c)10d)20Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two pipes of inner diameter 100 mm and outer diameter 110 mm each are joined by flash butt welding using 30 V power supply. At the interface, 1 mm of material melts from each pipe which has a resistance of 42.4 ohms. If the unit melt energy is 64.4 MJ/m3, then time required for welding (in s) is[ME 2010]a)1b)5c)10d)20Correct answer is option 'C'. Can you explain this answer?.
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Two pipes of inner diameter 100 mm and outer diameter 110 mm each are joined by flash butt welding using 30 V power supply. At the interface, 1 mm of material melts from each pipe which has a resistance of 42.4 ohms. If the unit melt energy is 64.4 MJ/m3, then time required for welding (in s) is[ME 2010]a)1b)5c)10d)20Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Two pipes of inner diameter 100 mm and outer diameter 110 mm each are joined by flash butt welding using 30 V power supply. At the interface, 1 mm of material melts from each pipe which has a resistance of 42.4 ohms. If the unit melt energy is 64.4 MJ/m3, then time required for welding (in s) is[ME 2010]a)1b)5c)10d)20Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Two pipes of inner diameter 100 mm and outer diameter 110 mm each are joined by flash butt welding using 30 V power supply. At the interface, 1 mm of material melts from each pipe which has a resistance of 42.4 ohms. If the unit melt energy is 64.4 MJ/m3, then time required for welding (in s) is[ME 2010]a)1b)5c)10d)20Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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