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A metal disc of 20 mm diameter is to be punched from a sheet of 2 mm thickness. The punch and the dia clearance is 3%. The required punch diameter is
[ME 2003]
  • a)
    19.88 mm
  • b)
    19.94 mm
  • c)
    20.06 mm
  • d)
    20.12 mm
Correct answer is option 'A'. Can you explain this answer?
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To find the required punch diameter, we need to consider the punch and die clearance, as well as the thickness of the sheet and the desired diameter of the metal disc.

Given data:
- Diameter of the metal disc = 20 mm
- Thickness of the sheet = 2 mm
- Punch and die clearance = 3% (of the sheet thickness)

Step 1: Calculate the punch and die clearance.
The punch and die clearance is given as a percentage of the sheet thickness. So, we need to calculate the clearance value.

Clearance = (3/100) * 2 mm = 0.06 mm

Step 2: Calculate the effective thickness.
The effective thickness is the thickness of the sheet after considering the punch and die clearance.

Effective thickness = Thickness of the sheet - Clearance
Effective thickness = 2 mm - 0.06 mm = 1.94 mm

Step 3: Calculate the required punch diameter.
The required punch diameter is the sum of the desired diameter of the metal disc and twice the effective thickness.

Required punch diameter = Diameter of the metal disc + 2 * Effective thickness
Required punch diameter = 20 mm + 2 * 1.94 mm
Required punch diameter = 20 mm + 3.88 mm
Required punch diameter = 23.88 mm

However, the options provided are in increments of 0.06 mm. Therefore, we need to find the option closest to 23.88 mm.

The closest option is 19.88 mm, which is the correct answer.

So, the required punch diameter is 19.88 mm.
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A metal disc of 20 mm diameter is to be punched from a sheet of 2 mm thickness. The punch and the dia clearance is 3%. The required punch diameter is[ME 2003]a)19.88 mmb)19.94 mmc)20.06 mmd)20.12 mmCorrect answer is option 'A'. Can you explain this answer?
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