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ΔABC is a right angled triangle, with ∠B = 90o, AB = 20 cm and BC = 21cm. A circle with centre O is inscribed in triangle ABC. OD, OE and OF are perpendiculars drawn on the sides AB, BC and CA respectively. Find the ratio of the area of the quadrilateral FOEC to the area of the quadrilateral ADOF.
(2015)
  • a)
    15 : 14
  • b)
    14 : 15
  • c)
    12 : 11
  • d)
    7 : 5
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
ΔABC is a right angled triangle, with ∠B = 90o, AB = 20 cm a...

∴  AB = 20
BC = 21

and (20 – r) + (21 – r) = 29
or, 2r = 41 – 29
⇒ r = 6 cm
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Most Upvoted Answer
ΔABC is a right angled triangle, with ∠B = 90o, AB = 20 cm a...

∴  AB = 20
BC = 21

and (20 – r) + (21 – r) = 29
or, 2r = 41 – 29
⇒ r = 6 cm
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Community Answer
ΔABC is a right angled triangle, with ∠B = 90o, AB = 20 cm a...
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ΔABC is a right angled triangle, with ∠B = 90o, AB = 20 cm and BC = 21cm. A circle with centre O is inscribed in triangle ABC. OD,OE and OF are perpendiculars drawn on the sides AB, BC and CA respectively. Find the ratio of the area of the quadrilateral FOECto the area of the quadrilateral ADOF.(2015)a)15 : 14b)14 : 15c)12 : 11d)7 : 5Correct answer is option 'A'. Can you explain this answer?
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