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The mean free path of benzene molecule is 6times10^(-6)m and average speed of molecules is 1.2times10^(3)m/s .The collision rate of molecules is?
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The mean free path of benzene molecule is 6times10^(-6)m and average s...

Answer:

- Mean Free Path and Average Speed:
Given that the mean free path of a benzene molecule is 6 x 10^(-6) m and the average speed of the molecules is 1.2 x 10^3 m/s.
- Collision Rate Calculation:
The collision rate of molecules can be calculated using the formula:
Collision rate = (Average speed) / (Mean free path)
- Substitute the Values:
Substitute the values we have:
Collision rate = 1.2 x 10^3 m/s / 6 x 10^(-6) m
Collision rate = 200,000 collisions per second
- Explanation:
This means that on average, a benzene molecule will collide with other molecules 200,000 times per second. This collision rate is determined by the speed at which the molecules are moving and the distance they travel between collisions, known as the mean free path.
- Conclusion:
Understanding the collision rate of molecules is important in various fields of study, such as chemistry, physics, and engineering. It helps in determining the behavior of gases and other substances at a molecular level.
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The mean free path of benzene molecule is 6times10^(-6)m and average speed of molecules is 1.2times10^(3)m/s .The collision rate of molecules is?
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The mean free path of benzene molecule is 6times10^(-6)m and average speed of molecules is 1.2times10^(3)m/s .The collision rate of molecules is? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The mean free path of benzene molecule is 6times10^(-6)m and average speed of molecules is 1.2times10^(3)m/s .The collision rate of molecules is? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The mean free path of benzene molecule is 6times10^(-6)m and average speed of molecules is 1.2times10^(3)m/s .The collision rate of molecules is?.
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