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If f(x + 2) = f(x) + f(x + 1) for all positive integers x, and f(11) = 91, f(15) = 617, then f(10) equals


(2018)

  • a)
    55

  • b)
    54

  • c)
    52

  • d)
    51

Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If f(x + 2) = f(x) + f(x + 1) for all positive integers x, and f(11) =...
Calculation:


⇒ f(x + 2) = f(x) + f(x + 1)


⇒ f(15) = f(13) + f(14)


⇒ f(13) + f(14) = 617  - (1)


⇒ f(12) + f(13) = f(14) - (2)


⇒ f(11) + f(12) = f(13) - (3)


By solving,


⇒ f(12) + f(13) = 617 - f(13)   [ using (1) and  (2) ]


⇒ 2f(11) + 3f(12) = 617  [ usining (3) ] 


⇒ f(12) = 145


⇒ f(12) = f(11) + f(10)


∴ f(10) = 54
Free Test
Community Answer
If f(x + 2) = f(x) + f(x + 1) for all positive integers x, and f(11) =...
f(x + 2) = f(x) + f(x + 1)
f(11) = 91
Let f(12) = a
f(13) = 91 + a
f(14) = 91 + 2a
f(15) = 182 + 3a = 617
⇒ a = 145
Now, f(10) = f(12) – f(11) = 145 – 91 = 54
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If f(x + 2) = f(x) + f(x + 1) for all positive integers x, and f(11) = 91, f(15) = 617, then f(10) equals(2018)a)55b)54c)52d)51Correct answer is option 'B'. Can you explain this answer?
Question Description
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