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A small element at the critical section of a component in biaxial state of stress with the two principal stresses being 360 MPa and 140 MPa. The maximum working stress according to distortion energy theory is
[1997]
  • a)
    220 MPa
  • b)
    110 MPa
  • c)
    314 MPa
  • d)
    330 MPa
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A small element at the critical section of a component in biaxial stat...
According to distortion energy theorem

 = 314.32 MPa
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Most Upvoted Answer
A small element at the critical section of a component in biaxial stat...
To determine the maximum working stress according to the distortion energy theory, we need to calculate the equivalent stress using the principal stresses. The distortion energy theory, also known as the von Mises criterion, states that failure occurs when the distortion energy per unit volume exceeds a certain value.

The equation to calculate the equivalent stress is given by:

σ_eq = √[(σ1 - σ2)^2 + (σ2 - σ3)^2 + (σ3 - σ1)^2]

where σ1, σ2, and σ3 are the principal stresses.

Given that the principal stresses are 360 MPa and 140 MPa, we can substitute these values into the equation:

σ_eq = √[(360 - 140)^2 + (140 - 0)^2 + (0 - 360)^2]

Simplifying the equation:

σ_eq = √[(220)^2 + (140)^2 + (360)^2]
= √(48400 + 19600 + 129600)
= √197600
= 314 MPa

Therefore, the maximum working stress according to the distortion energy theory is 314 MPa, which corresponds to option C.
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A small element at the critical section of a component in biaxial state of stress with the two principal stresses being 360 MPa and 140 MPa. The maximum working stress according to distortion energy theory is[1997]a)220 MPab)110 MPac)314 MPad)330 MPaCorrect answer is option 'C'. Can you explain this answer?
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