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Colligative property measurement is one of the techniques used in the measurement of chemical quantities with reasonable accuracy.
If a 40.65 gm sample of K2SO4 and BaSO4 is dissolved in 900 gm of pure water to form a solution 'A' at 57°C, its vapour pressure is found to be 39.6 torr while vapour pressure of pure water at 57°C is 40 torr. Density of solution A is 1.24 gm/ml.
In a different experiment when small amount of pure BaSO4 is mixed with water at 57°C it gives the osmotic rise of 4.05 x 10-5 atm. (R = 0.082 Lt.-atm/mol-K ; K = 39, Ba = 137, S = 32, 0 = 16)
Q.
Boiling point of solution A is (Kb water = 0.54 K-kg/mol) :
- a)0.3K
- b)0.1K
- c)0.04K
- d)0.05 K
Correct answer is option 'A'. Can you explain this answer?
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Colligative property measurement is one of the techniques used in the ...
Boiling Point Elevation
Boiling point elevation is one of the colligative properties of solutions. It is defined as the difference between the boiling point of a solution and the boiling point of the pure solvent. The boiling point elevation ΔTb is given by the formula:
ΔTb = Kb × m
where Kb is the molal boiling point elevation constant of the solvent, and m is the molality of the solute in the solution.
Calculation
Given:
Mass of K2SO4 + BaSO4 = 40.65 g
Mass of water = 900 g
Vapour pressure of solution A = 39.6 torr
Vapour pressure of pure water = 40 torr
Density of solution A = 1.24 g/mL
Osmotic rise of BaSO4 solution = 4.05 × 10^-5 atm
Kb of water = 0.54 K kg/mol
First, we need to calculate the molality of the solution.
Molality
Molality of the solution is given by the formula:
m = moles of solute / mass of solvent (in kg)
Moles of K2SO4 = 40.65 g / (174.27 g/mol) = 0.233 mol
Moles of BaSO4 = 40.65 g / (233.38 g/mol) = 0.174 mol
Total moles of solute = 0.233 + 0.174 = 0.407 mol
Mass of water = 900 g = 0.9 kg
m = 0.407 mol / 0.9 kg = 0.452 mol/kg
Vapour Pressure Lowering
The vapour pressure of a solution is lower than the vapour pressure of the pure solvent. The lowering of vapour pressure is given by the formula:
ΔP = Xsolute × Psolvent
where Xsolute is the mole fraction of the solute and Psolvent is the vapour pressure of the pure solvent.
From the given data, we can calculate the mole fraction of the solute:
Moles of K2SO4 = 0.233 mol
Moles of BaSO4 = 0.174 mol
Total moles of solute = 0.407 mol
Mole fraction of K2SO4 = 0.233 / 0.407 = 0.572
Mole fraction of BaSO4 = 0.174 / 0.407 = 0.428
Using Raoult's law, we can calculate the vapour pressure of the solution:
Psolution = Xwater × Pwater
where Xwater is the mole fraction of water and Pwater is the vapour pressure of pure water.
Mole fraction of water = 1 - (0.572 + 0.428) = 0.0
Therefore, Psolution = 0.0 × 40 torr = 0 torr
Boiling Point Elevation
Boiling point elevation is given by the formula:
ΔTb = Kb × m
Substituting the values, we get:
ΔTb = 0.54 K kg/mol × 0.452 mol/kg = 0.244 K
Therefore, the boiling point of solution A is:
Boiling point
Boiling point elevation is one of the colligative properties of solutions. It is defined as the difference between the boiling point of a solution and the boiling point of the pure solvent. The boiling point elevation ΔTb is given by the formula:
ΔTb = Kb × m
where Kb is the molal boiling point elevation constant of the solvent, and m is the molality of the solute in the solution.
Calculation
Given:
Mass of K2SO4 + BaSO4 = 40.65 g
Mass of water = 900 g
Vapour pressure of solution A = 39.6 torr
Vapour pressure of pure water = 40 torr
Density of solution A = 1.24 g/mL
Osmotic rise of BaSO4 solution = 4.05 × 10^-5 atm
Kb of water = 0.54 K kg/mol
First, we need to calculate the molality of the solution.
Molality
Molality of the solution is given by the formula:
m = moles of solute / mass of solvent (in kg)
Moles of K2SO4 = 40.65 g / (174.27 g/mol) = 0.233 mol
Moles of BaSO4 = 40.65 g / (233.38 g/mol) = 0.174 mol
Total moles of solute = 0.233 + 0.174 = 0.407 mol
Mass of water = 900 g = 0.9 kg
m = 0.407 mol / 0.9 kg = 0.452 mol/kg
Vapour Pressure Lowering
The vapour pressure of a solution is lower than the vapour pressure of the pure solvent. The lowering of vapour pressure is given by the formula:
ΔP = Xsolute × Psolvent
where Xsolute is the mole fraction of the solute and Psolvent is the vapour pressure of the pure solvent.
From the given data, we can calculate the mole fraction of the solute:
Moles of K2SO4 = 0.233 mol
Moles of BaSO4 = 0.174 mol
Total moles of solute = 0.407 mol
Mole fraction of K2SO4 = 0.233 / 0.407 = 0.572
Mole fraction of BaSO4 = 0.174 / 0.407 = 0.428
Using Raoult's law, we can calculate the vapour pressure of the solution:
Psolution = Xwater × Pwater
where Xwater is the mole fraction of water and Pwater is the vapour pressure of pure water.
Mole fraction of water = 1 - (0.572 + 0.428) = 0.0
Therefore, Psolution = 0.0 × 40 torr = 0 torr
Boiling Point Elevation
Boiling point elevation is given by the formula:
ΔTb = Kb × m
Substituting the values, we get:
ΔTb = 0.54 K kg/mol × 0.452 mol/kg = 0.244 K
Therefore, the boiling point of solution A is:
Boiling point
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Colligative property measurement is one of the techniques used in the measurement of chemical quantities with reasonable accuracy.If a 40.65 gm sample of K2SO4 and BaSO4 is dissolved in 900 gm of pure water to form a solution A at 57C, its vapour pressure is found to be 39.6 torr while vapour pressure of pure water at 57C is 40 torr. Density of solution A is 1.24 gm/ml.In a different experiment when small amount of pure BaSO4 is mixed with water at 57C it gives the osmotic rise of 4.05 x 10-5 atm. (R = 0.082 Lt.-atm/mol-K ; K = 39, Ba = 137, S = 32, 0 = 16)Q.Boiling point of solution A is (Kb water = 0.54 K-kg/mol) :a)0.3Kb)0.1Kc)0.04Kd) 0.05 KCorrect answer is option 'A'. Can you explain this answer?
Question Description
Colligative property measurement is one of the techniques used in the measurement of chemical quantities with reasonable accuracy.If a 40.65 gm sample of K2SO4 and BaSO4 is dissolved in 900 gm of pure water to form a solution A at 57C, its vapour pressure is found to be 39.6 torr while vapour pressure of pure water at 57C is 40 torr. Density of solution A is 1.24 gm/ml.In a different experiment when small amount of pure BaSO4 is mixed with water at 57C it gives the osmotic rise of 4.05 x 10-5 atm. (R = 0.082 Lt.-atm/mol-K ; K = 39, Ba = 137, S = 32, 0 = 16)Q.Boiling point of solution A is (Kb water = 0.54 K-kg/mol) :a)0.3Kb)0.1Kc)0.04Kd) 0.05 KCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Colligative property measurement is one of the techniques used in the measurement of chemical quantities with reasonable accuracy.If a 40.65 gm sample of K2SO4 and BaSO4 is dissolved in 900 gm of pure water to form a solution A at 57C, its vapour pressure is found to be 39.6 torr while vapour pressure of pure water at 57C is 40 torr. Density of solution A is 1.24 gm/ml.In a different experiment when small amount of pure BaSO4 is mixed with water at 57C it gives the osmotic rise of 4.05 x 10-5 atm. (R = 0.082 Lt.-atm/mol-K ; K = 39, Ba = 137, S = 32, 0 = 16)Q.Boiling point of solution A is (Kb water = 0.54 K-kg/mol) :a)0.3Kb)0.1Kc)0.04Kd) 0.05 KCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Colligative property measurement is one of the techniques used in the measurement of chemical quantities with reasonable accuracy.If a 40.65 gm sample of K2SO4 and BaSO4 is dissolved in 900 gm of pure water to form a solution A at 57C, its vapour pressure is found to be 39.6 torr while vapour pressure of pure water at 57C is 40 torr. Density of solution A is 1.24 gm/ml.In a different experiment when small amount of pure BaSO4 is mixed with water at 57C it gives the osmotic rise of 4.05 x 10-5 atm. (R = 0.082 Lt.-atm/mol-K ; K = 39, Ba = 137, S = 32, 0 = 16)Q.Boiling point of solution A is (Kb water = 0.54 K-kg/mol) :a)0.3Kb)0.1Kc)0.04Kd) 0.05 KCorrect answer is option 'A'. Can you explain this answer?.
Colligative property measurement is one of the techniques used in the measurement of chemical quantities with reasonable accuracy.If a 40.65 gm sample of K2SO4 and BaSO4 is dissolved in 900 gm of pure water to form a solution A at 57C, its vapour pressure is found to be 39.6 torr while vapour pressure of pure water at 57C is 40 torr. Density of solution A is 1.24 gm/ml.In a different experiment when small amount of pure BaSO4 is mixed with water at 57C it gives the osmotic rise of 4.05 x 10-5 atm. (R = 0.082 Lt.-atm/mol-K ; K = 39, Ba = 137, S = 32, 0 = 16)Q.Boiling point of solution A is (Kb water = 0.54 K-kg/mol) :a)0.3Kb)0.1Kc)0.04Kd) 0.05 KCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Colligative property measurement is one of the techniques used in the measurement of chemical quantities with reasonable accuracy.If a 40.65 gm sample of K2SO4 and BaSO4 is dissolved in 900 gm of pure water to form a solution A at 57C, its vapour pressure is found to be 39.6 torr while vapour pressure of pure water at 57C is 40 torr. Density of solution A is 1.24 gm/ml.In a different experiment when small amount of pure BaSO4 is mixed with water at 57C it gives the osmotic rise of 4.05 x 10-5 atm. (R = 0.082 Lt.-atm/mol-K ; K = 39, Ba = 137, S = 32, 0 = 16)Q.Boiling point of solution A is (Kb water = 0.54 K-kg/mol) :a)0.3Kb)0.1Kc)0.04Kd) 0.05 KCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Colligative property measurement is one of the techniques used in the measurement of chemical quantities with reasonable accuracy.If a 40.65 gm sample of K2SO4 and BaSO4 is dissolved in 900 gm of pure water to form a solution A at 57C, its vapour pressure is found to be 39.6 torr while vapour pressure of pure water at 57C is 40 torr. Density of solution A is 1.24 gm/ml.In a different experiment when small amount of pure BaSO4 is mixed with water at 57C it gives the osmotic rise of 4.05 x 10-5 atm. (R = 0.082 Lt.-atm/mol-K ; K = 39, Ba = 137, S = 32, 0 = 16)Q.Boiling point of solution A is (Kb water = 0.54 K-kg/mol) :a)0.3Kb)0.1Kc)0.04Kd) 0.05 KCorrect answer is option 'A'. Can you explain this answer?.
Solutions for Colligative property measurement is one of the techniques used in the measurement of chemical quantities with reasonable accuracy.If a 40.65 gm sample of K2SO4 and BaSO4 is dissolved in 900 gm of pure water to form a solution A at 57C, its vapour pressure is found to be 39.6 torr while vapour pressure of pure water at 57C is 40 torr. Density of solution A is 1.24 gm/ml.In a different experiment when small amount of pure BaSO4 is mixed with water at 57C it gives the osmotic rise of 4.05 x 10-5 atm. (R = 0.082 Lt.-atm/mol-K ; K = 39, Ba = 137, S = 32, 0 = 16)Q.Boiling point of solution A is (Kb water = 0.54 K-kg/mol) :a)0.3Kb)0.1Kc)0.04Kd) 0.05 KCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Here you can find the meaning of Colligative property measurement is one of the techniques used in the measurement of chemical quantities with reasonable accuracy.If a 40.65 gm sample of K2SO4 and BaSO4 is dissolved in 900 gm of pure water to form a solution A at 57C, its vapour pressure is found to be 39.6 torr while vapour pressure of pure water at 57C is 40 torr. Density of solution A is 1.24 gm/ml.In a different experiment when small amount of pure BaSO4 is mixed with water at 57C it gives the osmotic rise of 4.05 x 10-5 atm. (R = 0.082 Lt.-atm/mol-K ; K = 39, Ba = 137, S = 32, 0 = 16)Q.Boiling point of solution A is (Kb water = 0.54 K-kg/mol) :a)0.3Kb)0.1Kc)0.04Kd) 0.05 KCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Colligative property measurement is one of the techniques used in the measurement of chemical quantities with reasonable accuracy.If a 40.65 gm sample of K2SO4 and BaSO4 is dissolved in 900 gm of pure water to form a solution A at 57C, its vapour pressure is found to be 39.6 torr while vapour pressure of pure water at 57C is 40 torr. Density of solution A is 1.24 gm/ml.In a different experiment when small amount of pure BaSO4 is mixed with water at 57C it gives the osmotic rise of 4.05 x 10-5 atm. (R = 0.082 Lt.-atm/mol-K ; K = 39, Ba = 137, S = 32, 0 = 16)Q.Boiling point of solution A is (Kb water = 0.54 K-kg/mol) :a)0.3Kb)0.1Kc)0.04Kd) 0.05 KCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for Colligative property measurement is one of the techniques used in the measurement of chemical quantities with reasonable accuracy.If a 40.65 gm sample of K2SO4 and BaSO4 is dissolved in 900 gm of pure water to form a solution A at 57C, its vapour pressure is found to be 39.6 torr while vapour pressure of pure water at 57C is 40 torr. Density of solution A is 1.24 gm/ml.In a different experiment when small amount of pure BaSO4 is mixed with water at 57C it gives the osmotic rise of 4.05 x 10-5 atm. (R = 0.082 Lt.-atm/mol-K ; K = 39, Ba = 137, S = 32, 0 = 16)Q.Boiling point of solution A is (Kb water = 0.54 K-kg/mol) :a)0.3Kb)0.1Kc)0.04Kd) 0.05 KCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of Colligative property measurement is one of the techniques used in the measurement of chemical quantities with reasonable accuracy.If a 40.65 gm sample of K2SO4 and BaSO4 is dissolved in 900 gm of pure water to form a solution A at 57C, its vapour pressure is found to be 39.6 torr while vapour pressure of pure water at 57C is 40 torr. Density of solution A is 1.24 gm/ml.In a different experiment when small amount of pure BaSO4 is mixed with water at 57C it gives the osmotic rise of 4.05 x 10-5 atm. (R = 0.082 Lt.-atm/mol-K ; K = 39, Ba = 137, S = 32, 0 = 16)Q.Boiling point of solution A is (Kb water = 0.54 K-kg/mol) :a)0.3Kb)0.1Kc)0.04Kd) 0.05 KCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Colligative property measurement is one of the techniques used in the measurement of chemical quantities with reasonable accuracy.If a 40.65 gm sample of K2SO4 and BaSO4 is dissolved in 900 gm of pure water to form a solution A at 57C, its vapour pressure is found to be 39.6 torr while vapour pressure of pure water at 57C is 40 torr. Density of solution A is 1.24 gm/ml.In a different experiment when small amount of pure BaSO4 is mixed with water at 57C it gives the osmotic rise of 4.05 x 10-5 atm. (R = 0.082 Lt.-atm/mol-K ; K = 39, Ba = 137, S = 32, 0 = 16)Q.Boiling point of solution A is (Kb water = 0.54 K-kg/mol) :a)0.3Kb)0.1Kc)0.04Kd) 0.05 KCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
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