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If (1 0 x 0 1 0)2 (1 1 y 1)2 = (1 0 z 1 1)2, then what are the possible values of the binary digits x, y, z respectively? 
  • a)
    0, 0, 1
  • b)
    0, 1, 0
  • c)
    1, 1, 0
  • d)
    0, 0, 0
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If (1 0 x 0 1 0)2 (1 1 y 1)2 = (1 0 z 1 1)2, then what are the possibl...
Explanation:

Given equation:
(1 0 x 0 1 0)2 (1 1 y 1)2 = (1 0 z 1 1)2

Expanding the given equation:
(1 0 x 0 1 0)2 = 1 0 x 0 1 0
(1 1 y 1)2 = 1 1 y 1
(1 0 z 1 1)2 = 1 0 z 1 1

Equation becomes:
1 0 x 0 1 0 * 1 1 y 1 = 1 0 z 1 1

Performing the multiplication:
1 0 0 0 1 0
1 1 y 1
---------
1 0 z 1 1

Calculating the multiplication:
1st bit: 1 * 1 = 1 (carry 0)
2nd bit: 0 * 1 = 0 (carry 1)
3rd bit: x + 1 = z (carry 0)
4th bit: 0 + y = 1 (carry 0)
5th bit: 1 = 1 (no carry)
6th bit: 0 = 1 (carry 0)
From the calculation, we can determine the possible values of x, y, z:
x = 0 (since 0 + 1 = z)
y = 1 (to get 1 in the 4th bit)
z = 0 (from the calculation)
Therefore, the possible values of the binary digits x, y, z are 0, 1, 0 respectively, which matches with option B.
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If (1 0 x 0 1 0)2 (1 1 y 1)2 = (1 0 z 1 1)2, then what are the possible values of the binary digits x, y, z respectively?a)0, 0, 1b)0, 1, 0c)1, 1, 0d)0, 0, 0Correct answer is option 'B'. Can you explain this answer?
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