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A gas is heated in a duct as it flows over a resistance heater. Consider a 101 kW electric heating system. The gas enters the heating section of the duct at 100 kPa and 27°C with a volume flow rate of 15 m3/s. If heat is lost from the gas in the duct to the surroundings at a rate of 51 kW, the exit temperature of the gas is (Assume constant pressure, ideal gas, negligible change in kinetic and potential energies and constant specific heat : Cp = 1 kJ/kg. K; R = 0.5 kJ/kg K).
[2019 , Set 1]
- a)37°C
- b)76°C
- c)53°C
- d)32°C
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A gas is heated in a duct as it flows over a resistance heater. Consid...
By applying steady flow energy equation, (SFEE)
10 × 1 × 300 + (-51) = 10 × 1 × T2 + (-101)
T2 = 305 K = 32°C
Hence, Exit temperature (T2) = 32°C.
Most Upvoted Answer
A gas is heated in a duct as it flows over a resistance heater. Consid...
°C. The flow rate of the gas is 10 kg/s. The specific heat capacity of the gas is 1 kJ/kg·°C. The gas leaves the heating section at 200 kPa. Neglecting any heat loss to the surroundings, calculate the temperature of the gas as it leaves the heating section.
To solve this problem, we can use the equation:
Q = m * cp * (T2 - T1)
Where:
Q = heat transfer (in kW)
m = mass flow rate (in kg/s)
cp = specific heat capacity (in kJ/kg·°C)
T2 = final temperature (in °C)
T1 = initial temperature (in °C)
We are given:
Q = 101 kW
m = 10 kg/s
cp = 1 kJ/kg·°C
T1 = 27 °C
Rearranging the equation to solve for T2:
T2 = (Q / (m * cp)) + T1
Substituting the given values:
T2 = (101 kW / (10 kg/s * 1 kJ/kg·°C)) + 27 °C
T2 = (101,000 J/s / 10 kg/s) + 27 °C
T2 = 10,100 J/kg + 27 °C
Now, we need to convert the heat transfer from J/kg to °C by dividing by the specific heat capacity:
T2 = (10,100 J/kg / 1 kJ/kg·°C) + 27 °C
T2 = 10.1 °C + 27 °C
T2 = 37.1 °C
Therefore, the temperature of the gas as it leaves the heating section is 37.1 °C.
To solve this problem, we can use the equation:
Q = m * cp * (T2 - T1)
Where:
Q = heat transfer (in kW)
m = mass flow rate (in kg/s)
cp = specific heat capacity (in kJ/kg·°C)
T2 = final temperature (in °C)
T1 = initial temperature (in °C)
We are given:
Q = 101 kW
m = 10 kg/s
cp = 1 kJ/kg·°C
T1 = 27 °C
Rearranging the equation to solve for T2:
T2 = (Q / (m * cp)) + T1
Substituting the given values:
T2 = (101 kW / (10 kg/s * 1 kJ/kg·°C)) + 27 °C
T2 = (101,000 J/s / 10 kg/s) + 27 °C
T2 = 10,100 J/kg + 27 °C
Now, we need to convert the heat transfer from J/kg to °C by dividing by the specific heat capacity:
T2 = (10,100 J/kg / 1 kJ/kg·°C) + 27 °C
T2 = 10.1 °C + 27 °C
T2 = 37.1 °C
Therefore, the temperature of the gas as it leaves the heating section is 37.1 °C.
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A gas is heated in a duct as it flows over a resistance heater. Consider a 101 kW electric heating system. The gas enters the heating section of the duct at 100 kPa and 27°C with a volume flow rate of 15 m3/s. If heat is lost from the gas in the duct to the surroundings at a rate of 51 kW, the exit temperature of the gas is (Assume constant pressure, ideal gas, negligible change in kinetic and potential energies and constant specific heat : Cp = 1 kJ/kg. K; R = 0.5 kJ/kg K).[2019 , Set 1]a)37°Cb)76°Cc)53°Cd)32°CCorrect answer is option 'D'. Can you explain this answer?
Question Description
A gas is heated in a duct as it flows over a resistance heater. Consider a 101 kW electric heating system. The gas enters the heating section of the duct at 100 kPa and 27°C with a volume flow rate of 15 m3/s. If heat is lost from the gas in the duct to the surroundings at a rate of 51 kW, the exit temperature of the gas is (Assume constant pressure, ideal gas, negligible change in kinetic and potential energies and constant specific heat : Cp = 1 kJ/kg. K; R = 0.5 kJ/kg K).[2019 , Set 1]a)37°Cb)76°Cc)53°Cd)32°CCorrect answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A gas is heated in a duct as it flows over a resistance heater. Consider a 101 kW electric heating system. The gas enters the heating section of the duct at 100 kPa and 27°C with a volume flow rate of 15 m3/s. If heat is lost from the gas in the duct to the surroundings at a rate of 51 kW, the exit temperature of the gas is (Assume constant pressure, ideal gas, negligible change in kinetic and potential energies and constant specific heat : Cp = 1 kJ/kg. K; R = 0.5 kJ/kg K).[2019 , Set 1]a)37°Cb)76°Cc)53°Cd)32°CCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A gas is heated in a duct as it flows over a resistance heater. Consider a 101 kW electric heating system. The gas enters the heating section of the duct at 100 kPa and 27°C with a volume flow rate of 15 m3/s. If heat is lost from the gas in the duct to the surroundings at a rate of 51 kW, the exit temperature of the gas is (Assume constant pressure, ideal gas, negligible change in kinetic and potential energies and constant specific heat : Cp = 1 kJ/kg. K; R = 0.5 kJ/kg K).[2019 , Set 1]a)37°Cb)76°Cc)53°Cd)32°CCorrect answer is option 'D'. Can you explain this answer?.
A gas is heated in a duct as it flows over a resistance heater. Consider a 101 kW electric heating system. The gas enters the heating section of the duct at 100 kPa and 27°C with a volume flow rate of 15 m3/s. If heat is lost from the gas in the duct to the surroundings at a rate of 51 kW, the exit temperature of the gas is (Assume constant pressure, ideal gas, negligible change in kinetic and potential energies and constant specific heat : Cp = 1 kJ/kg. K; R = 0.5 kJ/kg K).[2019 , Set 1]a)37°Cb)76°Cc)53°Cd)32°CCorrect answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A gas is heated in a duct as it flows over a resistance heater. Consider a 101 kW electric heating system. The gas enters the heating section of the duct at 100 kPa and 27°C with a volume flow rate of 15 m3/s. If heat is lost from the gas in the duct to the surroundings at a rate of 51 kW, the exit temperature of the gas is (Assume constant pressure, ideal gas, negligible change in kinetic and potential energies and constant specific heat : Cp = 1 kJ/kg. K; R = 0.5 kJ/kg K).[2019 , Set 1]a)37°Cb)76°Cc)53°Cd)32°CCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A gas is heated in a duct as it flows over a resistance heater. Consider a 101 kW electric heating system. The gas enters the heating section of the duct at 100 kPa and 27°C with a volume flow rate of 15 m3/s. If heat is lost from the gas in the duct to the surroundings at a rate of 51 kW, the exit temperature of the gas is (Assume constant pressure, ideal gas, negligible change in kinetic and potential energies and constant specific heat : Cp = 1 kJ/kg. K; R = 0.5 kJ/kg K).[2019 , Set 1]a)37°Cb)76°Cc)53°Cd)32°CCorrect answer is option 'D'. Can you explain this answer?.
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A gas is heated in a duct as it flows over a resistance heater. Consider a 101 kW electric heating system. The gas enters the heating section of the duct at 100 kPa and 27°C with a volume flow rate of 15 m3/s. If heat is lost from the gas in the duct to the surroundings at a rate of 51 kW, the exit temperature of the gas is (Assume constant pressure, ideal gas, negligible change in kinetic and potential energies and constant specific heat : Cp = 1 kJ/kg. K; R = 0.5 kJ/kg K).[2019 , Set 1]a)37°Cb)76°Cc)53°Cd)32°CCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for A gas is heated in a duct as it flows over a resistance heater. Consider a 101 kW electric heating system. The gas enters the heating section of the duct at 100 kPa and 27°C with a volume flow rate of 15 m3/s. If heat is lost from the gas in the duct to the surroundings at a rate of 51 kW, the exit temperature of the gas is (Assume constant pressure, ideal gas, negligible change in kinetic and potential energies and constant specific heat : Cp = 1 kJ/kg. K; R = 0.5 kJ/kg K).[2019 , Set 1]a)37°Cb)76°Cc)53°Cd)32°CCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of A gas is heated in a duct as it flows over a resistance heater. Consider a 101 kW electric heating system. The gas enters the heating section of the duct at 100 kPa and 27°C with a volume flow rate of 15 m3/s. If heat is lost from the gas in the duct to the surroundings at a rate of 51 kW, the exit temperature of the gas is (Assume constant pressure, ideal gas, negligible change in kinetic and potential energies and constant specific heat : Cp = 1 kJ/kg. K; R = 0.5 kJ/kg K).[2019 , Set 1]a)37°Cb)76°Cc)53°Cd)32°CCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A gas is heated in a duct as it flows over a resistance heater. Consider a 101 kW electric heating system. The gas enters the heating section of the duct at 100 kPa and 27°C with a volume flow rate of 15 m3/s. If heat is lost from the gas in the duct to the surroundings at a rate of 51 kW, the exit temperature of the gas is (Assume constant pressure, ideal gas, negligible change in kinetic and potential energies and constant specific heat : Cp = 1 kJ/kg. K; R = 0.5 kJ/kg K).[2019 , Set 1]a)37°Cb)76°Cc)53°Cd)32°CCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
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