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The contents of a well-insulated tank are heated by a resistor of 23 W in which 10 A current is flowing. Consider the tank along with its contents as a thermodynamic system. The work done by the system and the heat transfer to the system are positive. The rates of heat (Q), work (W) and change in internal energy (ΔU) during the process (kW) are
[2011]
  • a)
    Q = 0, W = -2.3, ΔU = +2.3
  • b)
    Q = +2.3, W = 0, ΔU = +2.3
  • c)
    Q = -2.3, W = 0, ΔU = -2.3
  • d)
    Q = 0, W = + 2.3, ΔU = -2.3
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The contents of a well-insulated tank are heated by a resistor of 23 W...

= (102 x 20) watts = - 2.3 kW (on system)
First law : Q - w = ΔU
∴ 0 - (- Welectric) = Δu
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Most Upvoted Answer
The contents of a well-insulated tank are heated by a resistor of 23 W...
ΔU) can be calculated using the following equations:

Q = mcΔT
W = VI
ΔU = Q - W

Where:
Q = heat transfer to the system
W = work done by the system
ΔU = change in internal energy
m = mass of the contents in the tank
c = specific heat capacity of the contents
ΔT = change in temperature
V = voltage across the resistor
I = current flowing through the resistor

Given:
Resistor power (P) = 23 W
Current (I) = 10 A

To calculate the heat transfer, we need to know the specific heat capacity and change in temperature of the contents in the tank.

If you provide these values, I can help you calculate the heat transfer, work done, and change in internal energy.
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The contents of a well-insulated tank are heated by a resistor of 23 W in which 10 A current is flowing. Consider the tank along with its contents as a thermodynamic system. The work done by the system and the heat transfer to the system are positive. The rates of heat (Q), work (W) and change in internal energy (ΔU) during the process (kW) are[2011]a)Q = 0, W = -2.3, ΔU = +2.3b)Q = +2.3, W = 0, ΔU = +2.3c)Q = -2.3, W = 0, ΔU = -2.3d)Q = 0, W = + 2.3, ΔU = -2.3Correct answer is option 'A'. Can you explain this answer?
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The contents of a well-insulated tank are heated by a resistor of 23 W in which 10 A current is flowing. Consider the tank along with its contents as a thermodynamic system. The work done by the system and the heat transfer to the system are positive. The rates of heat (Q), work (W) and change in internal energy (ΔU) during the process (kW) are[2011]a)Q = 0, W = -2.3, ΔU = +2.3b)Q = +2.3, W = 0, ΔU = +2.3c)Q = -2.3, W = 0, ΔU = -2.3d)Q = 0, W = + 2.3, ΔU = -2.3Correct answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The contents of a well-insulated tank are heated by a resistor of 23 W in which 10 A current is flowing. Consider the tank along with its contents as a thermodynamic system. The work done by the system and the heat transfer to the system are positive. The rates of heat (Q), work (W) and change in internal energy (ΔU) during the process (kW) are[2011]a)Q = 0, W = -2.3, ΔU = +2.3b)Q = +2.3, W = 0, ΔU = +2.3c)Q = -2.3, W = 0, ΔU = -2.3d)Q = 0, W = + 2.3, ΔU = -2.3Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The contents of a well-insulated tank are heated by a resistor of 23 W in which 10 A current is flowing. Consider the tank along with its contents as a thermodynamic system. The work done by the system and the heat transfer to the system are positive. The rates of heat (Q), work (W) and change in internal energy (ΔU) during the process (kW) are[2011]a)Q = 0, W = -2.3, ΔU = +2.3b)Q = +2.3, W = 0, ΔU = +2.3c)Q = -2.3, W = 0, ΔU = -2.3d)Q = 0, W = + 2.3, ΔU = -2.3Correct answer is option 'A'. Can you explain this answer?.
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