Introduction
To determine if 8A5146B is divisible by 88 and to find the value of A×B.

Solution
To be divisible by 88, the number must be divisible by both 8 and 11.

Divisibility by 8
A number is divisible by 8 if the last three digits are divisible by 8. Since the last three digits are 46B, we need to check if this is divisible by 8.

Divisibility by 11
A number is divisible by 11 if the difference between the sum of the digits at odd places and the sum of the digits at even places is either 0 or a multiple of 11. In this case, the number has six digits, so we need to consider the odd and even places as follows:

Odd places: 8, 5, 4
Even places: A, 1, 6

The sum of the digits at odd places is 8 + 5 + 4 = 17, and the sum of the digits at even places is A + 1 + 6 = A + 7. Therefore, the difference between the two sums is (A + 7) - 17 = A - 10.

If this difference is a multiple of 11, then the number is divisible by 11. Therefore, we need to find the value of A that makes A - 10 a multiple of 11.

Final Step
The multiples of 11 that are less than or equal to 99 are: 0, 11, 22, 33, 44, 55, 66, 77, 88, and 99.

Therefore, A - 10 must be one of these multiples. Since A is a single digit, the only possible value for A is 1. This makes A - 10 = -9, which is equal to -11 + 2. Therefore, we need to add 11 to the difference and subtract 2 from A to get the next multiple of 11: A - 2 = 9, so A = 11.

Since A cannot be greater than 9, this is not possible. Therefore, the number 8A5146B is not divisible by 88.

Conclusion
The value of A×B cannot be determined as the number is not divisible by 88.