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Please solve this question. Water is flowing from a horizontal pipe fixed at a height of 2m from ground if it falls at a horizontal distance of 3m then the speed of water when it leaves the pipe is a)47m/s b)4.7m/s c)7.4m/s d) 14.7m/s
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Please solve this question. Water is flowing from a horizontal pipe fi...
Time taken by water to reach ground = √(2h/g)horizontal velocity of water × time taken to reach ground = range (which is 3m in question)v × (√(2×2/10)) = 3=> v = 3/(√0.4)=> v ≈ 4.7m/soption B
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Please solve this question. Water is flowing from a horizontal pipe fi...
Problem:
Water is flowing from a horizontal pipe fixed at a height of 2m from the ground. If it falls at a horizontal distance of 3m, then the speed of water when it leaves the pipe is:
a) 47m/s
b) 4.7m/s
c) 7.4m/s
d) 14.7m/s

Solution:

To find the speed of water when it leaves the pipe, we can use the principle of conservation of energy. The potential energy at the height of the pipe is converted into kinetic energy when the water falls.

Step 1: Identify the given information:
- Height of the pipe (h) = 2m
- Horizontal distance traveled (x) = 3m

Step 2: Calculate the potential energy:
The potential energy of an object at height h is given by the formula:
Potential energy (PE) = mgh
where m is the mass, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height.

In this case, the height is 2m. Since we don't have the mass of the water, we can cancel it out by dividing both sides of the equation by m:
PE/m = gh

Step 3: Calculate the kinetic energy:
The kinetic energy (KE) of an object is given by the formula:
KE = 0.5mv^2
where m is the mass and v is the velocity.

Since we canceled out the mass in Step 2, we can rewrite the equation as:
PE/m = KE/m

Step 4: Equate the potential energy and kinetic energy:
PE/m = KE/m
gh = 0.5v^2

Step 5: Solve for the velocity:
Rearrange the equation to solve for v:
v^2 = 2gh
v = sqrt(2gh)

Step 6: Substitute the given values and calculate the velocity:
Substituting the values of g (9.8 m/s^2) and h (2m) into the equation:
v = sqrt(2 * 9.8 * 2)
v = sqrt(39.2)
v ≈ 6.26 m/s

Step 7: Convert the velocity to the desired unit:
The speed is required in m/s, so rounding the value:
v ≈ 6.26 m/s

Answer:
Therefore, the speed of water when it leaves the pipe is approximately 6.26 m/s. None of the given options (a, b, c, d) matches the calculated value.
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Please solve this question. Water is flowing from a horizontal pipe fixed at a height of 2m from ground if it falls at a horizontal distance of 3m then the speed of water when it leaves the pipe is a)47m/s b)4.7m/s c)7.4m/s d) 14.7m/s
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Please solve this question. Water is flowing from a horizontal pipe fixed at a height of 2m from ground if it falls at a horizontal distance of 3m then the speed of water when it leaves the pipe is a)47m/s b)4.7m/s c)7.4m/s d) 14.7m/s for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Please solve this question. Water is flowing from a horizontal pipe fixed at a height of 2m from ground if it falls at a horizontal distance of 3m then the speed of water when it leaves the pipe is a)47m/s b)4.7m/s c)7.4m/s d) 14.7m/s covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Please solve this question. Water is flowing from a horizontal pipe fixed at a height of 2m from ground if it falls at a horizontal distance of 3m then the speed of water when it leaves the pipe is a)47m/s b)4.7m/s c)7.4m/s d) 14.7m/s.
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