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The orbital velocity of an artificial satellite in a circular orbit just above the earth’s surface is v0. The orbital velocity of satellite orbiting at an altitude of double the radius of earth is V0/√n Then the value of n is :
Correct answer is '3'. Can you explain this answer?
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The orbital velocity of an artificial satellite in a circular orbit just above the Earth can be calculated using the formula:
V = √(GM/R)
Where:
V is the orbital velocity,
G is the gravitational constant (approximately 6.67430 x 10^-11 m^3 kg^-1 s^-2),
M is the mass of the Earth (approximately 5.97219 x 10^24 kg), and
R is the radius of the orbit (distance between the satellite and the center of the Earth).
The radius of the orbit can be calculated by adding the radius of the Earth to the altitude of the satellite above the Earth's surface.
For example, if the altitude of the satellite is 500 kilometers (500,000 meters), and the radius of the Earth is approximately 6,371 kilometers (6,371,000 meters), then the radius of the orbit would be:
R = 6,371,000 + 500,000 = 6,871,000 meters
Using this value in the orbital velocity formula:
V = √((6.67430 x 10^-11) * (5.97219 x 10^24) / 6,871,000)
Calculating this expression will give you the orbital velocity of the satellite in meters per second.
V = √(GM/R)
Where:
V is the orbital velocity,
G is the gravitational constant (approximately 6.67430 x 10^-11 m^3 kg^-1 s^-2),
M is the mass of the Earth (approximately 5.97219 x 10^24 kg), and
R is the radius of the orbit (distance between the satellite and the center of the Earth).
The radius of the orbit can be calculated by adding the radius of the Earth to the altitude of the satellite above the Earth's surface.
For example, if the altitude of the satellite is 500 kilometers (500,000 meters), and the radius of the Earth is approximately 6,371 kilometers (6,371,000 meters), then the radius of the orbit would be:
R = 6,371,000 + 500,000 = 6,871,000 meters
Using this value in the orbital velocity formula:
V = √((6.67430 x 10^-11) * (5.97219 x 10^24) / 6,871,000)
Calculating this expression will give you the orbital velocity of the satellite in meters per second.
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The orbital velocity of an artificial satellite in a circular orbit just above the earth’s surface is v0. The orbital velocity of satellite orbiting at an altitude of double the radius of earth is V0/√nThen the value of n is :Correct answer is '3'. Can you explain this answer?
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