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Two tuning forks A and B vibrating simultaneously produce 5 beats. Frequency of B is 512. It is seen that if one arm of A is filed, then the number of beats increases. Frequency of A will be:-
Correct answer is '517'. Can you explain this answer?
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Most Upvoted Answer
Two tuning forks A and B vibrating simultaneously produce 5 beats. Fre...
After filling frequency increases, so nA increases(
). Also it is given that beat frequency increases (i.e., x
)
Hence nA
– nB = x ...(i) → Correct
nB – nA
= x
...(ii) → Wrong
⇒ nA = nB + x = 512 + 5 = 517 Hz.
). Also it is given that beat frequency increases (i.e., x)Hence nA
– nB = x ...(i) → CorrectnB – nA
= x ...(ii) → Wrong ⇒ nA = nB + x = 512 + 5 = 517 Hz.
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Community Answer
Two tuning forks A and B vibrating simultaneously produce 5 beats. Fre...
< b="" />Given Data< />
- Frequency of tuning fork B (fB) = 512 Hz
- Beats produced when A and B vibrate simultaneously = 5
- Beats increase when one arm of A is filed
< b="" />Calculations< />
- Let the frequency of tuning fork A be fA
- When A and B vibrate simultaneously, the frequency difference between them is equal to the number of beats produced: |fA - fB| = 5
< b="" />Analysis< />
- When one arm of A is filed, its frequency increases
- As a result, the number of beats produced will also increase
- This means that the frequency of A will increase from its initial value
< b="" />Solution< />
- Initially, |fA - fB| = 5
- After filing one arm of A, the number of beats increases
- Let the new frequency of A be f'A
- Therefore, |f'A - fB| > 5
- Since fB = 512 Hz, f'A must be greater than 512 Hz to produce more beats
- Hence, the frequency of A after filing one arm will be f'A = 512 + 5 = 517 Hz
Therefore, the frequency of tuning fork A is 517 Hz after filing one arm.
- Frequency of tuning fork B (fB) = 512 Hz
- Beats produced when A and B vibrate simultaneously = 5
- Beats increase when one arm of A is filed
< b="" />Calculations< />
- Let the frequency of tuning fork A be fA
- When A and B vibrate simultaneously, the frequency difference between them is equal to the number of beats produced: |fA - fB| = 5
< b="" />Analysis< />
- When one arm of A is filed, its frequency increases
- As a result, the number of beats produced will also increase
- This means that the frequency of A will increase from its initial value
< b="" />Solution< />
- Initially, |fA - fB| = 5
- After filing one arm of A, the number of beats increases
- Let the new frequency of A be f'A
- Therefore, |f'A - fB| > 5
- Since fB = 512 Hz, f'A must be greater than 512 Hz to produce more beats
- Hence, the frequency of A after filing one arm will be f'A = 512 + 5 = 517 Hz
Therefore, the frequency of tuning fork A is 517 Hz after filing one arm.
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Two tuning forks A and B vibrating simultaneously produce 5 beats. Frequency of B is 512. It is seen that if one arm of A is filed, then the number of beats increases. Frequency of A will be:-Correct answer is '517'. Can you explain this answer?
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Two tuning forks A and B vibrating simultaneously produce 5 beats. Frequency of B is 512. It is seen that if one arm of A is filed, then the number of beats increases. Frequency of A will be:-Correct answer is '517'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two tuning forks A and B vibrating simultaneously produce 5 beats. Frequency of B is 512. It is seen that if one arm of A is filed, then the number of beats increases. Frequency of A will be:-Correct answer is '517'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two tuning forks A and B vibrating simultaneously produce 5 beats. Frequency of B is 512. It is seen that if one arm of A is filed, then the number of beats increases. Frequency of A will be:-Correct answer is '517'. Can you explain this answer?.
Two tuning forks A and B vibrating simultaneously produce 5 beats. Frequency of B is 512. It is seen that if one arm of A is filed, then the number of beats increases. Frequency of A will be:-Correct answer is '517'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two tuning forks A and B vibrating simultaneously produce 5 beats. Frequency of B is 512. It is seen that if one arm of A is filed, then the number of beats increases. Frequency of A will be:-Correct answer is '517'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two tuning forks A and B vibrating simultaneously produce 5 beats. Frequency of B is 512. It is seen that if one arm of A is filed, then the number of beats increases. Frequency of A will be:-Correct answer is '517'. Can you explain this answer?.
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