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A monochromatic light of wavelength 6500Å is used in YDSE. Now both slits are covered by two thin slab of refractive index 3.2 and 2.7 respectively. By doing so central bright fringe shifts to original 7th bright fringe. If both slabs have same thickness then thickness of slab is (in µm).
    Correct answer is '9.10'. Can you explain this answer?
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    A monochromatic light of wavelength 6500Å is used in YDSE. Now b...
    Angstroms travels through air and enters a medium with an index of refraction of 1.5. What is the wavelength of the light inside the medium?

    The wavelength of light inside a medium can be calculated using the formula:

    λ = λ0 / n

    where λ is the wavelength of light inside the medium, λ0 is the wavelength of light in air, and n is the index of refraction of the medium.

    In this case, λ0 = 6500 Angstroms and n = 1.5. Plugging these values into the formula, we get:

    λ = 6500 / 1.5 = 4333.33 Angstroms

    Therefore, the wavelength of the light inside the medium is 4333.33 Angstroms.
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    A monochromatic light of wavelength 6500Å is used in YDSE. Now both slits are covered by two thin slab of refractive index 3.2 and 2.7 respectively. By doing so central bright fringe shifts to original 7thbright fringe. If both slabs have same thickness then thickness of slab is (in µm).Correct answer is '9.10'. Can you explain this answer?
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    A monochromatic light of wavelength 6500Å is used in YDSE. Now both slits are covered by two thin slab of refractive index 3.2 and 2.7 respectively. By doing so central bright fringe shifts to original 7thbright fringe. If both slabs have same thickness then thickness of slab is (in µm).Correct answer is '9.10'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A monochromatic light of wavelength 6500Å is used in YDSE. Now both slits are covered by two thin slab of refractive index 3.2 and 2.7 respectively. By doing so central bright fringe shifts to original 7thbright fringe. If both slabs have same thickness then thickness of slab is (in µm).Correct answer is '9.10'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A monochromatic light of wavelength 6500Å is used in YDSE. Now both slits are covered by two thin slab of refractive index 3.2 and 2.7 respectively. By doing so central bright fringe shifts to original 7thbright fringe. If both slabs have same thickness then thickness of slab is (in µm).Correct answer is '9.10'. Can you explain this answer?.
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