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A plastic circular disc of radius 10 cm is placed on a thin oil film of thickness 2 mm, spread over a flat horizontal surface. The torque (N-m) required to spin the disc about its central vertical axis with a constant angular velocity 8 rad/sec is (coefficient of viscosity of oil is 1.0 kg/m-s) (take π = 3.14)
Correct answer is between '0.62,0.63'. Can you explain this answer?
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A plastic circular disc of radius 10 cm is placed on a thin oil film o...
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A plastic circular disc of radius 10 cm is placed on a thin oil film o...
The density of oil as 800 kg/m^3)
We can use the formula for the torque required to overcome the viscous drag of the oil:
τ = 2πηr^3ω/3h
Where τ is the torque, η is the coefficient of viscosity, r is the radius of the disc, ω is the angular velocity, and h is the thickness of the oil film.
Substituting the given values, we get:
τ = 2π(1.0)(0.1)^3(8)/3(0.002)
τ = 0.167 N-m (rounded to three significant figures)
Therefore, the torque required to spin the disc about its central vertical axis with a constant angular velocity 8 rad/sec is 0.167 N-m.
We can use the formula for the torque required to overcome the viscous drag of the oil:
τ = 2πηr^3ω/3h
Where τ is the torque, η is the coefficient of viscosity, r is the radius of the disc, ω is the angular velocity, and h is the thickness of the oil film.
Substituting the given values, we get:
τ = 2π(1.0)(0.1)^3(8)/3(0.002)
τ = 0.167 N-m (rounded to three significant figures)
Therefore, the torque required to spin the disc about its central vertical axis with a constant angular velocity 8 rad/sec is 0.167 N-m.
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A plastic circular disc of radius 10 cm is placed on a thin oil film of thickness 2 mm, spread over a flat horizontal surface. The torque (N-m) required to spin the disc about its central vertical axis with a constant angular velocity 8 rad/sec is (coefficient of viscosity of oil is 1.0 kg/m-s) (take π = 3.14)Correct answer is between '0.62,0.63'. Can you explain this answer?
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A plastic circular disc of radius 10 cm is placed on a thin oil film of thickness 2 mm, spread over a flat horizontal surface. The torque (N-m) required to spin the disc about its central vertical axis with a constant angular velocity 8 rad/sec is (coefficient of viscosity of oil is 1.0 kg/m-s) (take π = 3.14)Correct answer is between '0.62,0.63'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A plastic circular disc of radius 10 cm is placed on a thin oil film of thickness 2 mm, spread over a flat horizontal surface. The torque (N-m) required to spin the disc about its central vertical axis with a constant angular velocity 8 rad/sec is (coefficient of viscosity of oil is 1.0 kg/m-s) (take π = 3.14)Correct answer is between '0.62,0.63'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A plastic circular disc of radius 10 cm is placed on a thin oil film of thickness 2 mm, spread over a flat horizontal surface. The torque (N-m) required to spin the disc about its central vertical axis with a constant angular velocity 8 rad/sec is (coefficient of viscosity of oil is 1.0 kg/m-s) (take π = 3.14)Correct answer is between '0.62,0.63'. Can you explain this answer?.
A plastic circular disc of radius 10 cm is placed on a thin oil film of thickness 2 mm, spread over a flat horizontal surface. The torque (N-m) required to spin the disc about its central vertical axis with a constant angular velocity 8 rad/sec is (coefficient of viscosity of oil is 1.0 kg/m-s) (take π = 3.14)Correct answer is between '0.62,0.63'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A plastic circular disc of radius 10 cm is placed on a thin oil film of thickness 2 mm, spread over a flat horizontal surface. The torque (N-m) required to spin the disc about its central vertical axis with a constant angular velocity 8 rad/sec is (coefficient of viscosity of oil is 1.0 kg/m-s) (take π = 3.14)Correct answer is between '0.62,0.63'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A plastic circular disc of radius 10 cm is placed on a thin oil film of thickness 2 mm, spread over a flat horizontal surface. The torque (N-m) required to spin the disc about its central vertical axis with a constant angular velocity 8 rad/sec is (coefficient of viscosity of oil is 1.0 kg/m-s) (take π = 3.14)Correct answer is between '0.62,0.63'. Can you explain this answer?.
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