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A point charge 2C is kept fixed at the origin, Another point charge 4C is brought from a far off point to a point distant 50 cm from the origin. Calculate the electrostatic potential energy of this two charge system. Another charge of 1uC brought to a point distant 100 cm from each of these two charges?
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A point charge 2C is kept fixed at the origin, Another point charge ...
Calculation of Electrostatic Potential Energy of a Two Charge System


Given Information:


  • Charge 1: 2C (fixed at origin)

  • Charge 2: 4C (distance of 50cm from origin)

  • Charge 3: 1uC (distance of 100cm from each of charge 1 and charge 2)



Calculation of Electrostatic Potential Energy:


  • The electrostatic potential energy of a two-charge system is given by the formula U = k*q1*q2/r, where k is the Coulomb constant, q1 and q2 are the charges and r is the distance between the charges.

  • For the given two-charge system, the electrostatic potential energy can be calculated as follows:


    • Charge 1 and Charge 2:


      • Distance between the two charges, r = 50cm = 0.5m

      • Charge 1, q1 = 2C

      • Charge 2, q2 = 4C

      • Using the formula, U = k*q1*q2/r = (9*10^9)*(2)*(4)/(0.5) = 72*10^9 J


    • Charge 1, Charge 2, and Charge 3:


      • The electrostatic potential energy of a three-charge system can be calculated by finding the sum of the electrostatic potential energies of the individual two-charge systems.

      • For the given three-charge system, the electrostatic potential energy can be calculated as follows:

      • Electrostatic potential energy of Charge 1 and Charge 3:


        • Distance between the two charges, r = 100cm = 1m

        • Charge 1, q1 = 2C

        • Charge 3, q2 = 1uC = 10^-6C

        • Using the formula, U1 = k*q1*q2/r = (9*10^9)*(2)*(10^-6)/(1) = 18 J


      • Electrostatic potential energy of Charge 2 and Charge 3:


        • Distance between the two charges, r = 100cm = 1m

        • Charge 2, q1 = 4C

        • Charge 3, q2 = 1uC = 10^-6C

        • Using the formula, U2 = k*q1*q2/r = (9*10^9)*(4)*(10^-6)/(1) = 36 J


      • Total electrostatic potential energy of the three-charge system:


        • U_total = U1 + U2 + U12 = 18 + 36 + 72*10^9 = 72*10^9 + 54 J






Conclusion:

The electrostatic potential energy of the two-charge
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A point charge 2C is kept fixed at the origin, Another point charge 4C is brought from a far off point to a point distant 50 cm from the origin. Calculate the electrostatic potential energy of this two charge system. Another charge of 1uC brought to a point distant 100 cm from each of these two charges?
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A point charge 2C is kept fixed at the origin, Another point charge 4C is brought from a far off point to a point distant 50 cm from the origin. Calculate the electrostatic potential energy of this two charge system. Another charge of 1uC brought to a point distant 100 cm from each of these two charges? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A point charge 2C is kept fixed at the origin, Another point charge 4C is brought from a far off point to a point distant 50 cm from the origin. Calculate the electrostatic potential energy of this two charge system. Another charge of 1uC brought to a point distant 100 cm from each of these two charges? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A point charge 2C is kept fixed at the origin, Another point charge 4C is brought from a far off point to a point distant 50 cm from the origin. Calculate the electrostatic potential energy of this two charge system. Another charge of 1uC brought to a point distant 100 cm from each of these two charges?.
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