If solution of equation3cos2andtheta; andndash; 2andradic;3sin andtheta; cos andtheta; andndash; 3sin2andtheta; = 0 are nandpi; +andpi;/rand nandpi; +andpi;/s then -r andndash; s- is equal to:-Correct answer is '9'. Can you explain this answer?

EduRev

All Courses

Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity

Open App

JEE Exam > JEE Questions > If solution of equation3cos2θ – 2...

Join the Discussion on the App

If solution of equation 3cos²θ – 2√3 sin θ cos θ – 3sin²θ = 0 are nπ + π/r and nπ + π/s then |r – s| is equal to:-

Correct answer is '9'. Can you explain this answer?

FREE This question is part of

JEE Main Maths Mock Test- 6

Attempt Test

Attempt this Test

Verified Answer

If solution of equation3cos2θ – 2√3sin θ cos &...

Equation can be written as
3tan²θ + 2√3 tanθ – 3 = 0
⇒ tan θ = 1/√3 and tan θ = -√3
⇒ θ = nπ + π/6 or θ = nπ – π/3
⇒ |r – s| = |6 + 3| = 9

View all questions of this test

View all answers Start learning for free

< Previous Question Next Question >

Explore Courses for JEE exam

Top Courses for JEEView all

Physics for JEE Main & Advanced

Mock Tests for JEE Main and Advanced 2025

Chemistry for JEE Main & Advanced

Mathematics (Maths) for JEE Main & Advanced

Chapter-wise Tests for JEE Main & Advanced

Top Courses for JEE

View all

If solution of equation3cos2θ – 2√3sin θ cos θ – 3sin2θ = 0 are nπ +π/rand nπ +π/s then |r – s| is equal to:-Correct answer is '9'. Can you explain this answer?

Share with a Friend

Answer this doubt

Question Description
If solution of equation3cos2θ – 2√3sin θ cos θ – 3sin2θ = 0 are nπ +π/rand nπ +π/s then |r – s| is equal to:-Correct answer is '9'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If solution of equation3cos2θ – 2√3sin θ cos θ – 3sin2θ = 0 are nπ +π/rand nπ +π/s then |r – s| is equal to:-Correct answer is '9'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If solution of equation3cos2θ – 2√3sin θ cos θ – 3sin2θ = 0 are nπ +π/rand nπ +π/s then |r – s| is equal to:-Correct answer is '9'. Can you explain this answer?.

Solutions for If solution of equation3cos2θ – 2√3sin θ cos θ – 3sin2θ = 0 are nπ +π/rand nπ +π/s then |r – s| is equal to:-Correct answer is '9'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of If solution of equation3cos2θ – 2√3sin θ cos θ – 3sin2θ = 0 are nπ +π/rand nπ +π/s then |r – s| is equal to:-Correct answer is '9'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of If solution of equation3cos2θ – 2√3sin θ cos θ – 3sin2θ = 0 are nπ +π/rand nπ +π/s then |r – s| is equal to:-Correct answer is '9'. Can you explain this answer?, a detailed solution for If solution of equation3cos2θ – 2√3sin θ cos θ – 3sin2θ = 0 are nπ +π/rand nπ +π/s then |r – s| is equal to:-Correct answer is '9'. Can you explain this answer? has been provided alongside types of If solution of equation3cos2θ – 2√3sin θ cos θ – 3sin2θ = 0 are nπ +π/rand nπ +π/s then |r – s| is equal to:-Correct answer is '9'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice If solution of equation3cos2θ – 2√3sin θ cos θ – 3sin2θ = 0 are nπ +π/rand nπ +π/s then |r – s| is equal to:-Correct answer is '9'. Can you explain this answer? tests, examples and also practice JEE tests.

Explore Courses for JEE exam