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When a photosensitive surface is illuminated with light of wavelength λ, the stopping potential is V. When the same surface is illuminated by light of wavelength 2λ, stopping potential is V/4. The threshold wavelength for the surface is nλ, n = ?
    Correct answer is '3'. Can you explain this answer?
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    When a photosensitive surface is illuminated with light of wavelength ...
    When a photosensitive surface is illuminated with light of a specific wavelength, several things can happen depending on the properties of the surface:

    1. Absorption: The photosensitive surface may absorb the light energy, converting it into electrical energy. This is the basis of photovoltaic cells, where light absorption generates an electric current.

    2. Reflection: The photosensitive surface may reflect the light back without absorbing it. This occurs if the surface is not sensitive to the specific wavelength of light.

    3. Transmission: The photosensitive surface may allow the light to pass through it without being absorbed or reflected. This is common in transparent materials like glass.

    4. Emission: In some cases, the photosensitive surface may emit light of a different wavelength after being illuminated. This is known as fluorescence or phosphorescence and occurs when the absorbed energy is released as light.

    The specific response of a photosensitive surface to light depends on its composition and structure. Different materials have different absorption and reflection properties at various wavelengths, making them suitable for specific applications in fields like photography, imaging sensors, solar cells, and optoelectronics.
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    When a photosensitive surface is illuminated with light of wavelength λ, the stopping potential is V. When the same surface is illuminated by light of wavelength 2λ, stopping potential is V/4. The threshold wavelength for the surface is nλ, n = ?Correct answer is '3'. Can you explain this answer?
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