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A simply supported beam of span 3.0 m has a cross-section 120 mm x 180mm. If the permissible stress in the material of the beam is 10N / mm ^ 2 determine (i)maximum udl it can carry (ii) maximum concentrated load at a point I m from support it can carry. Neglect moment due to self weight.?
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A simply supported beam of span 3.0 m has a cross-section 120 mm x 180...
Solution:
Given:
- Span of the beam (L) = 3.0 m
- Cross-section of the beam = 120 mm x 180mm
- Permissible stress in the material of the beam (σ) = 10N / mm ^ 2
(i) Maximum UDL it can carry:
The maximum UDL (W) that a simply supported beam can carry is given by the formula:
W = (σ * b * d)/6 * {(L/2)^2 + (d/2)^2}
Where,
- b = breadth of the beam = 120 mm
- d = depth of the beam = 180 mm
Substituting the given values in the above formula, we get:
W = (10 * 120 * 180)/6 * {(3/2)^2 + (180/2)^2} = 27.54 kN/m
Therefore, the maximum UDL the beam can carry is 27.54 kN/m.
(ii) Maximum concentrated load at a point 1 m from support it can carry:
The maximum concentrated load (Wc) that a simply supported beam can carry at a point 1 m from the support is given by the formula:
Wc = (4 * σ * b * d)/3
Substituting the given values in the above formula, we get:
Wc = (4 * 10 * 120 * 180)/3 = 34.56 kN
Therefore, the maximum concentrated load the beam can carry at a point 1 m from the support is 34.56 kN.
Explanation:
The given problem is solved using the formulae for maximum UDL and maximum concentrated load that a simply supported beam can carry. The maximum UDL is calculated based on the cross-section of the beam, permissible stress in the material of the beam, and span of the beam. The maximum concentrated load is calculated based on the cross-section of the beam and permissible stress in the material of the beam. The neglect of the moment due to self-weight of the beam is assumed in the problem.
Given:
- Span of the beam (L) = 3.0 m
- Cross-section of the beam = 120 mm x 180mm
- Permissible stress in the material of the beam (σ) = 10N / mm ^ 2
(i) Maximum UDL it can carry:
The maximum UDL (W) that a simply supported beam can carry is given by the formula:
W = (σ * b * d)/6 * {(L/2)^2 + (d/2)^2}
Where,
- b = breadth of the beam = 120 mm
- d = depth of the beam = 180 mm
Substituting the given values in the above formula, we get:
W = (10 * 120 * 180)/6 * {(3/2)^2 + (180/2)^2} = 27.54 kN/m
Therefore, the maximum UDL the beam can carry is 27.54 kN/m.
(ii) Maximum concentrated load at a point 1 m from support it can carry:
The maximum concentrated load (Wc) that a simply supported beam can carry at a point 1 m from the support is given by the formula:
Wc = (4 * σ * b * d)/3
Substituting the given values in the above formula, we get:
Wc = (4 * 10 * 120 * 180)/3 = 34.56 kN
Therefore, the maximum concentrated load the beam can carry at a point 1 m from the support is 34.56 kN.
Explanation:
The given problem is solved using the formulae for maximum UDL and maximum concentrated load that a simply supported beam can carry. The maximum UDL is calculated based on the cross-section of the beam, permissible stress in the material of the beam, and span of the beam. The maximum concentrated load is calculated based on the cross-section of the beam and permissible stress in the material of the beam. The neglect of the moment due to self-weight of the beam is assumed in the problem.
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A simply supported beam of span 3.0 m has a cross-section 120 mm x 180mm. If the permissible stress in the material of the beam is 10N / mm ^ 2 determine (i)maximum udl it can carry (ii) maximum concentrated load at a point I m from support it can carry. Neglect moment due to self weight.?
Question Description
A simply supported beam of span 3.0 m has a cross-section 120 mm x 180mm. If the permissible stress in the material of the beam is 10N / mm ^ 2 determine (i)maximum udl it can carry (ii) maximum concentrated load at a point I m from support it can carry. Neglect moment due to self weight.? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A simply supported beam of span 3.0 m has a cross-section 120 mm x 180mm. If the permissible stress in the material of the beam is 10N / mm ^ 2 determine (i)maximum udl it can carry (ii) maximum concentrated load at a point I m from support it can carry. Neglect moment due to self weight.? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A simply supported beam of span 3.0 m has a cross-section 120 mm x 180mm. If the permissible stress in the material of the beam is 10N / mm ^ 2 determine (i)maximum udl it can carry (ii) maximum concentrated load at a point I m from support it can carry. Neglect moment due to self weight.?.
A simply supported beam of span 3.0 m has a cross-section 120 mm x 180mm. If the permissible stress in the material of the beam is 10N / mm ^ 2 determine (i)maximum udl it can carry (ii) maximum concentrated load at a point I m from support it can carry. Neglect moment due to self weight.? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A simply supported beam of span 3.0 m has a cross-section 120 mm x 180mm. If the permissible stress in the material of the beam is 10N / mm ^ 2 determine (i)maximum udl it can carry (ii) maximum concentrated load at a point I m from support it can carry. Neglect moment due to self weight.? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A simply supported beam of span 3.0 m has a cross-section 120 mm x 180mm. If the permissible stress in the material of the beam is 10N / mm ^ 2 determine (i)maximum udl it can carry (ii) maximum concentrated load at a point I m from support it can carry. Neglect moment due to self weight.?.
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