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An aqueous solution of 6.3 g of oxalic acid dihydrate is made upto 250 mL. The volume of0.1 N NaOH required to completely neutralise 10 mL of this solution is :
Correct answer is '40'. Can you explain this answer?
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An aqueous solution of 6.3 g of oxalic acid dihydrate is made upto 250...
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Calculation of Volume of 0.1 N NaOH Required
- First, calculate the molarity of oxalic acid dihydrate solution:
- Molar mass of oxalic acid dihydrate (C2H2O4.2H2O) = 126.07 g/mol
- Number of moles of oxalic acid dihydrate = 6.3 g / 126.07 g/mol = 0.05 mol
- Volume of solution = 250 mL = 0.25 L
- Molarity of oxalic acid dihydrate = 0.05 mol / 0.25 L = 0.2 M
- Next, calculate the number of moles of oxalic acid dihydrate in 10 mL of solution:
- Number of moles of oxalic acid dihydrate in 10 mL = 0.2 M x 0.01 L = 0.002 mol
- Since oxalic acid dihydrate is a dibasic acid, it will require twice the moles of NaOH for neutralization:
- Number of moles of NaOH required = 2 x 0.002 mol = 0.004 mol
- Finally, calculate the volume of 0.1 N NaOH required to neutralize 0.004 mol:
- Volume of 0.1 N NaOH required = 0.004 mol / 0.1 mol/L = 0.04 L = 40 mL
Therefore, the volume of 0.1 N NaOH required to completely neutralize 10 mL of the oxalic acid dihydrate solution is 40 mL.
- First, calculate the molarity of oxalic acid dihydrate solution:
- Molar mass of oxalic acid dihydrate (C2H2O4.2H2O) = 126.07 g/mol
- Number of moles of oxalic acid dihydrate = 6.3 g / 126.07 g/mol = 0.05 mol
- Volume of solution = 250 mL = 0.25 L
- Molarity of oxalic acid dihydrate = 0.05 mol / 0.25 L = 0.2 M
- Next, calculate the number of moles of oxalic acid dihydrate in 10 mL of solution:
- Number of moles of oxalic acid dihydrate in 10 mL = 0.2 M x 0.01 L = 0.002 mol
- Since oxalic acid dihydrate is a dibasic acid, it will require twice the moles of NaOH for neutralization:
- Number of moles of NaOH required = 2 x 0.002 mol = 0.004 mol
- Finally, calculate the volume of 0.1 N NaOH required to neutralize 0.004 mol:
- Volume of 0.1 N NaOH required = 0.004 mol / 0.1 mol/L = 0.04 L = 40 mL
Therefore, the volume of 0.1 N NaOH required to completely neutralize 10 mL of the oxalic acid dihydrate solution is 40 mL.
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An aqueous solution of 6.3 g of oxalic acid dihydrate is made upto 250 mL. The volume of0.1 N NaOH required to completely neutralise 10 mL of this solution is :Correct answer is '40'. Can you explain this answer?
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An aqueous solution of 6.3 g of oxalic acid dihydrate is made upto 250 mL. The volume of0.1 N NaOH required to completely neutralise 10 mL of this solution is :Correct answer is '40'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An aqueous solution of 6.3 g of oxalic acid dihydrate is made upto 250 mL. The volume of0.1 N NaOH required to completely neutralise 10 mL of this solution is :Correct answer is '40'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An aqueous solution of 6.3 g of oxalic acid dihydrate is made upto 250 mL. The volume of0.1 N NaOH required to completely neutralise 10 mL of this solution is :Correct answer is '40'. Can you explain this answer?.
An aqueous solution of 6.3 g of oxalic acid dihydrate is made upto 250 mL. The volume of0.1 N NaOH required to completely neutralise 10 mL of this solution is :Correct answer is '40'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An aqueous solution of 6.3 g of oxalic acid dihydrate is made upto 250 mL. The volume of0.1 N NaOH required to completely neutralise 10 mL of this solution is :Correct answer is '40'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An aqueous solution of 6.3 g of oxalic acid dihydrate is made upto 250 mL. The volume of0.1 N NaOH required to completely neutralise 10 mL of this solution is :Correct answer is '40'. Can you explain this answer?.
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