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Let the resultant of three forces of magnitude 5N, 12N, & 13N acting on a body be zero. If sin23° = 5/13, then angle between 5N & 13 N force (in degree) will be:
Correct answer is '113'. Can you explain this answer?
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Let the resultant of three forces of magnitude 5N, 12N, & 13N acti...
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Let the resultant of three forces of magnitude 5N, 12N, & 13N acti...
And 15N acting at a point be F. Find the magnitude of F and the angle it makes with the 5N force.
We can use the parallelogram law of vector addition to find the resultant force F. We draw the three vectors as shown below:
[Insert image of three vectors]
We complete the parallelogram by drawing the diagonal from the tail of the 5N force to the head of the 15N force. The diagonal represents the resultant force F.
[Insert image of parallelogram and diagonal]
To find the magnitude of F, we use the Pythagorean theorem:
F^2 = (5N)^2 + (12N)^2 + (15N)^2
F^2 = 25N^2 + 144N^2 + 225N^2
F^2 = 394N^2
F = √394N ≈ 19.85N
To find the angle that F makes with the 5N force, we use trigonometry. We can see that the 5N force and the diagonal of the parallelogram form a right triangle, so we use the inverse tangent function:
tanθ = opposite/adjacent = (15N)/(5N+12N) = 1.0714
θ = tan^-1(1.0714) ≈ 47.22°
Therefore, the magnitude of the resultant force F is approximately 19.85N and it makes an angle of approximately 47.22° with the 5N force.
We can use the parallelogram law of vector addition to find the resultant force F. We draw the three vectors as shown below:
[Insert image of three vectors]
We complete the parallelogram by drawing the diagonal from the tail of the 5N force to the head of the 15N force. The diagonal represents the resultant force F.
[Insert image of parallelogram and diagonal]
To find the magnitude of F, we use the Pythagorean theorem:
F^2 = (5N)^2 + (12N)^2 + (15N)^2
F^2 = 25N^2 + 144N^2 + 225N^2
F^2 = 394N^2
F = √394N ≈ 19.85N
To find the angle that F makes with the 5N force, we use trigonometry. We can see that the 5N force and the diagonal of the parallelogram form a right triangle, so we use the inverse tangent function:
tanθ = opposite/adjacent = (15N)/(5N+12N) = 1.0714
θ = tan^-1(1.0714) ≈ 47.22°
Therefore, the magnitude of the resultant force F is approximately 19.85N and it makes an angle of approximately 47.22° with the 5N force.
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Let the resultant of three forces of magnitude 5N, 12N, & 13N acting on a body be zero. If sin23° = 5/13,then angle between 5N & 13 N force (in degree) will be:Correct answer is '113'. Can you explain this answer?
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Let the resultant of three forces of magnitude 5N, 12N, & 13N acting on a body be zero. If sin23° = 5/13,then angle between 5N & 13 N force (in degree) will be:Correct answer is '113'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Let the resultant of three forces of magnitude 5N, 12N, & 13N acting on a body be zero. If sin23° = 5/13,then angle between 5N & 13 N force (in degree) will be:Correct answer is '113'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let the resultant of three forces of magnitude 5N, 12N, & 13N acting on a body be zero. If sin23° = 5/13,then angle between 5N & 13 N force (in degree) will be:Correct answer is '113'. Can you explain this answer?.
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