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AB,A2 and B2 are diatomic molecules.If the bond enthalpies of A2,AB and B2 are in the ratio 1:1:0.5 and enthalpy of formation of AB from A2 and B2 is -100kJ/mole.What is the bond energy of A2?
Most Upvoted Answer
AB,A2 and B2 are diatomic molecules.If the bond enthalpies of A2,AB an...
Given
- Bond enthalpies: A2 - x, AB - x, B2 - 0.5x
- Enthalpy of formation of AB from A2 and B2: -100kJ/mole
To Find
Bond energy of A2 (x)
Solution
Enthalpy of formation of AB from A2 and B2 can be expressed as:
ΔH(f)°(AB) = [ΔH(bond)°(AB) - ΔH(bond)°(A2) - ΔH(bond)°(B2)]
Where ΔH(bond)° is the bond enthalpy of the molecule
Substituting the given values, we get:
-100 = [x - x - 0.5x]
-100 = -0.5x
x = 200 kJ/mol
Answer
The bond energy of A2 is 200 kJ/mol.
Community Answer
AB,A2 and B2 are diatomic molecules.If the bond enthalpies of A2,AB an...
let energy of formation of A2 be E,
then reaction is
1/2 A +1/2 B
2
2
-> ABenergy of o.5 mol A2 bond = 0.5 E
energy of o.5 mol B2 bond = 0.5 E/2 (as ratio is 0.5)
energy of 1 mol AB = E (as ratio 1)
total energy = E- 0.75E=0.25E that is -100
so E=-400kj/mol
energy of 1 mol AB = E (as ratio 1)
total energy = E- 0.75E=0.25E that is -100
so E=-400kj/mol
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AB,A2 and B2 are diatomic molecules.If the bond enthalpies of A2,AB and B2 are in the ratio 1:1:0.5 and enthalpy of formation of AB from A2 and B2 is -100kJ/mole.What is the bond energy of A2?
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