The given equation is s=10t 4t^2, where s is the distance travelled by the body in meters and t is the time in seconds. We need to find the acceleration of the body.


To calculate acceleration, we need to differentiate the equation with respect to time (t).

s = 10t - 4t^2
v = ds/dt = 10 - 8t
a = dv/dt = -8

Therefore, the acceleration of the body is -8 m/s^2. The negative sign indicates that the acceleration is in the opposite direction of the velocity.


The acceleration of the body is constant and equal to -8 m/s^2. This means that the velocity of the body is decreasing at a rate of 8 m/s^2. The body is slowing down. If the acceleration were positive, then the velocity would be increasing, and the body would be speeding up.

The acceleration is constant because the equation is a quadratic function with a coefficient of -4, which is the acceleration due to gravity. This means that the body is moving under the influence of gravity. The acceleration due to gravity is constant near the surface of the earth and is equal to 9.8 m/s^2.

In conclusion, the acceleration of the body is -8 m/s^2, which means that the body is slowing down at a constant rate. The negative sign indicates that the acceleration is in the opposite direction of the velocity. The body is moving under the influence of gravity, which is a constant acceleration near the surface of the earth.

We know that
s= ut+ 1/2at^2
and we re given
s= 10t+4t^2
since LHS are equal ,
on comparing we get ,
1/2a=4
a= 8m/s^2