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Which of the following reagents cannot be used to distinguish between hexanal and 2-hexanone?
- a)Tollen's reagent
- b)Br₂ in CCl₄
- c)I₂ in NaOH
- d)None of these
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
Which of the following reagents cannot be used to distinguish between ...
Explanation:
Tollens reagent:
- Tollens reagent is a reagent used to distinguish between aldehydes and ketones.
- It gives a silver mirror test with aldehydes but does not react with ketones.
- Therefore, it can be used to differentiate between hexanal (an aldehyde) and 2-hexanone (a ketone).
Br in CCl:
- Bromine in carbon tetrachloride is a reagent used for the bromine test.
- It reacts with alkenes to form dibromides, but it is not specific for distinguishing between hexanal and 2-hexanone.
- Therefore, it cannot be used to differentiate between these two compounds.
I in NaOH:
- Iodine in sodium hydroxide is a reagent used for the iodoform test.
- It reacts with methyl ketones to form a yellow precipitate of iodoform.
- While both hexanal and 2-hexanone can give a positive iodoform test, this test alone may not be sufficient to distinguish between the two compounds.
Conclusion:
- Among the given reagents, only Tollens reagent can be used to distinguish between hexanal and 2-hexanone.
- Br in CCl and I in NaOH are not specific enough to differentiate between these two compounds.
Tollens reagent:
- Tollens reagent is a reagent used to distinguish between aldehydes and ketones.
- It gives a silver mirror test with aldehydes but does not react with ketones.
- Therefore, it can be used to differentiate between hexanal (an aldehyde) and 2-hexanone (a ketone).
Br in CCl:
- Bromine in carbon tetrachloride is a reagent used for the bromine test.
- It reacts with alkenes to form dibromides, but it is not specific for distinguishing between hexanal and 2-hexanone.
- Therefore, it cannot be used to differentiate between these two compounds.
I in NaOH:
- Iodine in sodium hydroxide is a reagent used for the iodoform test.
- It reacts with methyl ketones to form a yellow precipitate of iodoform.
- While both hexanal and 2-hexanone can give a positive iodoform test, this test alone may not be sufficient to distinguish between the two compounds.
Conclusion:
- Among the given reagents, only Tollens reagent can be used to distinguish between hexanal and 2-hexanone.
- Br in CCl and I in NaOH are not specific enough to differentiate between these two compounds.
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Which of the following reagents cannot be used to distinguish between hexanal and 2-hexanone?a)Tollens reagentb)Br in CClc)I in NaOHd)None of theseCorrect answer is option 'B'. Can you explain this answer?
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