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Solution of (x+y-1) dx+(2x+2y-3) dy = 0 is
  • a)
    y+x+log (x+y-2)=c
  • b)
    y+2x+log (x+y-2)=c
  • c)
    2y+x+log(x+y-2)=c
  • d)
    2y+2x+log(x+y-2)=c
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Solution of (x+y-1) dx+(2x+2y-3) dy = 0 isa)y+x+log (x+y-2)=cb)y+2x+lo...
Given differential equation is (x y-1) dx + (2x 2y-3) dy = 0

Separating variables
(x y-1) dx = -(2x 2y-3) dy
Integrating both sides
∫ (x y-1) dx = -∫ (2x 2y-3) dy
=> 1/2 x^2 y - x = -x^2 y + 3y + C

Simplifying the above equation
=> 2x^2 y - 2x = -x^2 y + 3y + C
=> x^2 y = 2x + 3y + C

Taking logarithm on both sides
=> log(x^2 y) = log(2x + 3y + C)
=> log(x y^2) = log(2x + 3y + C)

Therefore, the answer is option (a) y x log(x y-2) = c.
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Solution of (x+y-1) dx+(2x+2y-3) dy = 0 isa)y+x+log (x+y-2)=cb)y+2x+log (x+y-2)=cc)2y+x+log(x+y-2)=cd)2y+2x+log(x+y-2)=cCorrect answer is option 'C'. Can you explain this answer?
Question Description
Solution of (x+y-1) dx+(2x+2y-3) dy = 0 isa)y+x+log (x+y-2)=cb)y+2x+log (x+y-2)=cc)2y+x+log(x+y-2)=cd)2y+2x+log(x+y-2)=cCorrect answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Solution of (x+y-1) dx+(2x+2y-3) dy = 0 isa)y+x+log (x+y-2)=cb)y+2x+log (x+y-2)=cc)2y+x+log(x+y-2)=cd)2y+2x+log(x+y-2)=cCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Solution of (x+y-1) dx+(2x+2y-3) dy = 0 isa)y+x+log (x+y-2)=cb)y+2x+log (x+y-2)=cc)2y+x+log(x+y-2)=cd)2y+2x+log(x+y-2)=cCorrect answer is option 'C'. Can you explain this answer?.
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