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If 750 is flowing through the resistance, what is the voltage drop across the resistor?
  • a)
    14.6 V
  • b)
    146 V
  • c)
    82.5 V
  • d)
    8.25 V
Correct answer is option 'D'. Can you explain this answer?
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To find the voltage drop across a resistor, we can use Ohm's Law, which states that the voltage drop (V) across a resistor is equal to the current (I) flowing through the resistor multiplied by the resistance (R) of the resistor.

The formula for Ohm's Law is:
V = I * R

In this case, the current flowing through the resistance is given as 750 Amps. We need to find the voltage drop across the resistor. Since the resistance is not given, we cannot directly calculate the voltage drop.

However, we can use the concept of power to find the resistance. Power (P) is given by the formula:
P = V * I

The power flowing through the resistor is not given, so we cannot directly calculate the resistance. However, we can make use of the fact that power is also given by the formula:
P = I^2 * R

By rearranging the formula, we can find the resistance:
R = P / I^2

Since the power is not given, we cannot calculate the resistance directly. Therefore, we cannot directly find the voltage drop across the resistor.

However, we can make some assumptions and calculations to estimate the voltage drop. Let's assume the resistance of the resistor is 1 Ohm. Using Ohm's Law, we can calculate the voltage drop as:
V = I * R
V = 750 * 1
V = 750 V

Therefore, if the resistance is 1 Ohm, the voltage drop across the resistor would be 750 Volts.

However, this is just an assumption and estimation based on the given information. Without the actual resistance value, we cannot accurately calculate the voltage drop across the resistor. Therefore, the correct answer would be to state that we cannot determine the voltage drop across the resistor with the given information.
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If 750 is flowing through the resistance, what is the voltage drop across the resistor?a)14.6 Vb)146 Vc)82.5 Vd)8.25 VCorrect answer is option 'D'. Can you explain this answer?
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