Class 12 Exam > Class 12 Questions > One plate of a capacitor is connected to a sp...
Start Learning for Free
One plate of a capacitor is connected to a spring.Area of both the plates is A and separation is d when the capacitor is uncharged.When capacitor is charged,in steady state separation between the plates is 0.8d.The force constant of the spring is
Verified Answer
One plate of a capacitor is connected to a spring.Area of both the pla...
During electrostatic equilibrium. Electrostatic attraction between the plates = spring force
This question is part of UPSC exam. View all Class 12 courses
Most Upvoted Answer
One plate of a capacitor is connected to a spring.Area of both the pla...
Explanation of the Force Constant of the Spring:
- Initial Configuration:
- Initially, when the capacitor is uncharged, the separation between the plates is d.
- The force between the plates is zero, as there is no electric field.
- Charged Configuration:
- When the capacitor is charged, in steady state, the separation between the plates decreases to 0.8d.
- This results in an electric field between the plates, causing a force on the charges.
- Force Acting on the Plates:
- The force acting on each plate of the capacitor is given by F = qE, where q is the charge on the plate and E is the electric field between the plates.
- Relation between Force and Spring Constant:
- The force acting on the plates of the capacitor is also the force acting on the spring when the plates are connected to it.
- This force causes a displacement in the spring, leading to the spring force kx, where k is the force constant of the spring and x is the displacement.
- Equilibrium Condition:
- At equilibrium, the forces due to the electric field and the spring are equal.
- Therefore, qE = kx, where qE is the force due to the electric field and kx is the spring force.
- Calculation of Force Constant:
- From the equilibrium condition, we can determine the force constant of the spring as k = qE/x.
- Substituting the values of q, E, and x in the equation will give us the force constant of the spring.
- Initial Configuration:
- Initially, when the capacitor is uncharged, the separation between the plates is d.
- The force between the plates is zero, as there is no electric field.
- Charged Configuration:
- When the capacitor is charged, in steady state, the separation between the plates decreases to 0.8d.
- This results in an electric field between the plates, causing a force on the charges.
- Force Acting on the Plates:
- The force acting on each plate of the capacitor is given by F = qE, where q is the charge on the plate and E is the electric field between the plates.
- Relation between Force and Spring Constant:
- The force acting on the plates of the capacitor is also the force acting on the spring when the plates are connected to it.
- This force causes a displacement in the spring, leading to the spring force kx, where k is the force constant of the spring and x is the displacement.
- Equilibrium Condition:
- At equilibrium, the forces due to the electric field and the spring are equal.
- Therefore, qE = kx, where qE is the force due to the electric field and kx is the spring force.
- Calculation of Force Constant:
- From the equilibrium condition, we can determine the force constant of the spring as k = qE/x.
- Substituting the values of q, E, and x in the equation will give us the force constant of the spring.
|
|
Explore Courses for Class 12 exam
|
|
Similar Class 12 Doubts
One plate of a capacitor is connected to a spring.Area of both the plates is A and separation is d when the capacitor is uncharged.When capacitor is charged,in steady state separation between the plates is 0.8d.The force constant of the spring is
Question Description
One plate of a capacitor is connected to a spring.Area of both the plates is A and separation is d when the capacitor is uncharged.When capacitor is charged,in steady state separation between the plates is 0.8d.The force constant of the spring is for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about One plate of a capacitor is connected to a spring.Area of both the plates is A and separation is d when the capacitor is uncharged.When capacitor is charged,in steady state separation between the plates is 0.8d.The force constant of the spring is covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One plate of a capacitor is connected to a spring.Area of both the plates is A and separation is d when the capacitor is uncharged.When capacitor is charged,in steady state separation between the plates is 0.8d.The force constant of the spring is.
One plate of a capacitor is connected to a spring.Area of both the plates is A and separation is d when the capacitor is uncharged.When capacitor is charged,in steady state separation between the plates is 0.8d.The force constant of the spring is for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about One plate of a capacitor is connected to a spring.Area of both the plates is A and separation is d when the capacitor is uncharged.When capacitor is charged,in steady state separation between the plates is 0.8d.The force constant of the spring is covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One plate of a capacitor is connected to a spring.Area of both the plates is A and separation is d when the capacitor is uncharged.When capacitor is charged,in steady state separation between the plates is 0.8d.The force constant of the spring is.
Solutions for One plate of a capacitor is connected to a spring.Area of both the plates is A and separation is d when the capacitor is uncharged.When capacitor is charged,in steady state separation between the plates is 0.8d.The force constant of the spring is in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of One plate of a capacitor is connected to a spring.Area of both the plates is A and separation is d when the capacitor is uncharged.When capacitor is charged,in steady state separation between the plates is 0.8d.The force constant of the spring is defined & explained in the simplest way possible. Besides giving the explanation of
One plate of a capacitor is connected to a spring.Area of both the plates is A and separation is d when the capacitor is uncharged.When capacitor is charged,in steady state separation between the plates is 0.8d.The force constant of the spring is, a detailed solution for One plate of a capacitor is connected to a spring.Area of both the plates is A and separation is d when the capacitor is uncharged.When capacitor is charged,in steady state separation between the plates is 0.8d.The force constant of the spring is has been provided alongside types of One plate of a capacitor is connected to a spring.Area of both the plates is A and separation is d when the capacitor is uncharged.When capacitor is charged,in steady state separation between the plates is 0.8d.The force constant of the spring is theory, EduRev gives you an
ample number of questions to practice One plate of a capacitor is connected to a spring.Area of both the plates is A and separation is d when the capacitor is uncharged.When capacitor is charged,in steady state separation between the plates is 0.8d.The force constant of the spring is tests, examples and also practice Class 12 tests.
|
|
Explore Courses for Class 12 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup