Class 12 Exam  >  Class 12 Questions  >  A 400 V 3-phase mesh connected synchronous mo... Start Learning for Free
A 400 V 3-phase mesh connected synchronous motor runs at rated voltage and with an excitation emf of 510 V. Its synchronous impedance per phase is 0.5 j4 ohm and friction windage and iron losses are 900 W. Calculate?
Verified Answer
A 400 V 3-phase mesh connected synchronous motor runs at rated voltage...
The input power supplied to the motor is:Input Power = (400V x 510V) / (0.5 j4 ohm) = 204 + 3220j VAInput Power = 3242 VAOutput Power = Input Power - LossesOutput Power = 3242 VA - 900 W= 2342 VA
This question is part of UPSC exam. View all Class 12 courses
Most Upvoted Answer
A 400 V 3-phase mesh connected synchronous motor runs at rated voltage...
Calculation of Power Factor

To calculate the power factor, we need to find the total impedance of the motor. The synchronous impedance per phase is given as 0.5+j4 ohm. Since it is a 3-phase motor, the total impedance will be three times the synchronous impedance.

Z = 3 * (0.5+j4) = 1.5+j12 ohm

The power factor can be calculated using the formula:

power factor = cos(θ) = Re(Z) / |Z|

where Re(Z) is the real part of the impedance and |Z| is the magnitude of the impedance.

Re(Z) = 1.5 ohm
|Z| = sqrt((1.5)^2 + (12)^2) = sqrt(226.5) ohm

power factor = 1.5 / sqrt(226.5) = 0.099

Calculation of Current

The current flowing through the motor is given by the formula:

I = V / Z

where V is the rated voltage and Z is the total impedance.

I = 400 V / (1.5+j12) ohm

To simplify the calculation, we can convert the impedance to polar form:

Z = sqrt((1.5)^2 + (12)^2) * e^(arctan(12/1.5))

I = 400 V / (sqrt(226.5) * e^(arctan(12/1.5)))

I = 400 / (sqrt(226.5) * e^(arctan(8)))

Now, we can calculate the magnitude and angle of the current:

|I| = 400 / (sqrt(226.5)) = 26.25 A
θ = arctan(8) = 80.54 degrees

Calculation of Active Power

The active power can be calculated using the formula:

P = 3 * |I|^2 * Re(Z) * power factor

P = 3 * (26.25)^2 * 1.5 * 0.099 = 4357.22 W

Calculation of Reactive Power

The reactive power can be calculated using the formula:

Q = 3 * |I|^2 * Re(Z) * sqrt(1 - power factor^2)

Q = 3 * (26.25)^2 * 1.5 * sqrt(1 - 0.099^2) = 12425.62 VAR

Calculation of Apparent Power

The apparent power can be calculated using the formula:

S = sqrt(P^2 + Q^2)

S = sqrt((4357.22)^2 + (12425.62)^2) = 13100.49 VA

Calculation of Power Factor Angle

The power factor angle can be calculated using the formula:

θ = arccos(power factor)

θ = arccos(0.099) = 84.12 degrees

Conclusion

- The power factor of the motor is 0.099, which indicates a lagging power factor.
- The current flowing through the motor is 26.25 A with an angle of 80.54 degrees.
- The active power consumed by the motor is 4357.22
Explore Courses for Class 12 exam

Similar Class 12 Doubts

A 400 V 3-phase mesh connected synchronous motor runs at rated voltage and with an excitation emf of 510 V. Its synchronous impedance per phase is 0.5 j4 ohm and friction windage and iron losses are 900 W. Calculate?
Question Description
A 400 V 3-phase mesh connected synchronous motor runs at rated voltage and with an excitation emf of 510 V. Its synchronous impedance per phase is 0.5 j4 ohm and friction windage and iron losses are 900 W. Calculate? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A 400 V 3-phase mesh connected synchronous motor runs at rated voltage and with an excitation emf of 510 V. Its synchronous impedance per phase is 0.5 j4 ohm and friction windage and iron losses are 900 W. Calculate? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 400 V 3-phase mesh connected synchronous motor runs at rated voltage and with an excitation emf of 510 V. Its synchronous impedance per phase is 0.5 j4 ohm and friction windage and iron losses are 900 W. Calculate?.
Solutions for A 400 V 3-phase mesh connected synchronous motor runs at rated voltage and with an excitation emf of 510 V. Its synchronous impedance per phase is 0.5 j4 ohm and friction windage and iron losses are 900 W. Calculate? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of A 400 V 3-phase mesh connected synchronous motor runs at rated voltage and with an excitation emf of 510 V. Its synchronous impedance per phase is 0.5 j4 ohm and friction windage and iron losses are 900 W. Calculate? defined & explained in the simplest way possible. Besides giving the explanation of A 400 V 3-phase mesh connected synchronous motor runs at rated voltage and with an excitation emf of 510 V. Its synchronous impedance per phase is 0.5 j4 ohm and friction windage and iron losses are 900 W. Calculate?, a detailed solution for A 400 V 3-phase mesh connected synchronous motor runs at rated voltage and with an excitation emf of 510 V. Its synchronous impedance per phase is 0.5 j4 ohm and friction windage and iron losses are 900 W. Calculate? has been provided alongside types of A 400 V 3-phase mesh connected synchronous motor runs at rated voltage and with an excitation emf of 510 V. Its synchronous impedance per phase is 0.5 j4 ohm and friction windage and iron losses are 900 W. Calculate? theory, EduRev gives you an ample number of questions to practice A 400 V 3-phase mesh connected synchronous motor runs at rated voltage and with an excitation emf of 510 V. Its synchronous impedance per phase is 0.5 j4 ohm and friction windage and iron losses are 900 W. Calculate? tests, examples and also practice Class 12 tests.
Explore Courses for Class 12 exam
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev