Ln a process at constant volume 24cal/gms of heat has been added to a system.Calculate the change in its temprature Ans-0.319T1K?

Question

Answer

To calculate the change in temperature when 24 cal/gms of heat is added to a system at constant volume, we can use the formula:

q = mcΔT

where q is the heat added, m is the mass of the system, c is the specific heat capacity of the system, and ΔT is the change in temperature.

In this case, the heat added is 24 cal/gms, and since we are given the heat per gram, we can assume the mass of the system is 1 gram. Therefore, m = 1g.

Next, we need to determine the specific heat capacity of the system. The specific heat capacity is the amount of heat required to raise the temperature of 1 gram of a substance by 1 degree Celsius.

Since the specific heat capacity is not given, we can assume it to be the specific heat capacity of water, which is approximately 1 cal/g°C.

Now we can substitute the values into the formula and solve for ΔT:

24 cal/gms = 1g x 1 cal/g°C x ΔT

Simplifying the equation, we have:

ΔT = 24 cal/gms / (1g x 1 cal/g°C)

ΔT = 24°C

Therefore, the change in temperature when 24 cal/gms of heat is added to the system at constant volume is 24°C.

Answer: ΔT = 24°C

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