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The r.m.s value of a half-wave rectified current is 100 A. Its value for full-wave rectification would be.......amperes.
- a)141.4
- b)200
- c)200/p
- d)40/p
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The r.m.s value of a half-wave rectified current is 100 A. Its value f...
Half-Wave Rectification:
- In half-wave rectification, only the positive half-cycles of the input AC current are allowed to pass through, while the negative half-cycles are blocked.
- The output current waveform is a series of pulses with a frequency twice that of the input AC current.
- The r.m.s value of the half-wave rectified current is given as 100 A.
Full-Wave Rectification:
- In full-wave rectification, both the positive and negative half-cycles of the input AC current are utilized.
- This can be achieved by using a bridge rectifier circuit or a center-tapped transformer.
- The output current waveform is a continuous waveform with a frequency equal to that of the input AC current.
- The r.m.s value for full-wave rectification can be calculated by taking the r.m.s value of the half-wave rectified current and multiplying it by a factor of √2.
Calculation:
- The r.m.s value for full-wave rectification = √2 * r.m.s value for half-wave rectification
- = √2 * 100 A (Given)
- ≈ 141.4 A (Approximately)
Therefore, the correct answer is option A) 141.4 amperes.
- In half-wave rectification, only the positive half-cycles of the input AC current are allowed to pass through, while the negative half-cycles are blocked.
- The output current waveform is a series of pulses with a frequency twice that of the input AC current.
- The r.m.s value of the half-wave rectified current is given as 100 A.
Full-Wave Rectification:
- In full-wave rectification, both the positive and negative half-cycles of the input AC current are utilized.
- This can be achieved by using a bridge rectifier circuit or a center-tapped transformer.
- The output current waveform is a continuous waveform with a frequency equal to that of the input AC current.
- The r.m.s value for full-wave rectification can be calculated by taking the r.m.s value of the half-wave rectified current and multiplying it by a factor of √2.
Calculation:
- The r.m.s value for full-wave rectification = √2 * r.m.s value for half-wave rectification
- = √2 * 100 A (Given)
- ≈ 141.4 A (Approximately)
Therefore, the correct answer is option A) 141.4 amperes.
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