Class 12 Exam > Class 12 Questions > At a given place on the Earth’s surface...
Start Learning for Free
At a given place on the Earth’s surface, the horizontal component of Earth’s magnetic field is 9 × 10-5 T and the resultant magnetic field is 180 × 10-6. Calculate the angle of dip at this place.
- a)45o
- b)0o
- c)60o
- d)30o
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
At a given place on the Earth’s surface, the horizontal componen...
Given: H = 9 × 10-5; R = 180 × 10-6 = 18 × 10-5
The required equation ➔ H=Rcosδ
Therefore, δ = cos-1 1/2
The required equation ➔ H=Rcosδ
Therefore, δ = cos-1 1/2
=60o
Thus, the angle of dip is 60o.
Thus, the angle of dip is 60o.
Most Upvoted Answer
At a given place on the Earth’s surface, the horizontal componen...
Given: H = 9 × 10-5; R = 180 × 10-6 = 18 × 10-5
The required equation ➔ H=Rcosδ
Therefore, δ = cos-1 1/2
The required equation ➔ H=Rcosδ
Therefore, δ = cos-1 1/2
=60o
Thus, the angle of dip is 60o.
Thus, the angle of dip is 60o.
Free Test
FREE
| Start Free Test |
Community Answer
At a given place on the Earth’s surface, the horizontal componen...
Given data:
Horizontal component of Earth's magnetic field (Bh) = 9 × 10^-5 T
Resultant magnetic field (B) = 180 × 10^-6 T
Calculating the angle of dip:
The angle of dip (θ) can be calculated using the formula:
B = Bh * cos(θ)
Given that B = 180 × 10^-6 T and Bh = 9 × 10^-5 T, we can rearrange the formula to solve for cos(θ):
cos(θ) = B / Bh
cos(θ) = (180 × 10^-6) / (9 × 10^-5)
cos(θ) = 0.02
To find the angle θ, we need to calculate the arccosine of 0.02:
θ = arccos(0.02)
θ ≈ 60°
Therefore, the angle of dip at this place is approximately 60°. Hence, the correct answer is option C - 60°.
Horizontal component of Earth's magnetic field (Bh) = 9 × 10^-5 T
Resultant magnetic field (B) = 180 × 10^-6 T
Calculating the angle of dip:
The angle of dip (θ) can be calculated using the formula:
B = Bh * cos(θ)
Given that B = 180 × 10^-6 T and Bh = 9 × 10^-5 T, we can rearrange the formula to solve for cos(θ):
cos(θ) = B / Bh
cos(θ) = (180 × 10^-6) / (9 × 10^-5)
cos(θ) = 0.02
To find the angle θ, we need to calculate the arccosine of 0.02:
θ = arccos(0.02)
θ ≈ 60°
Therefore, the angle of dip at this place is approximately 60°. Hence, the correct answer is option C - 60°.
|
Explore Courses for Class 12 exam
|
|
Similar Class 12 Doubts
At a given place on the Earth’s surface, the horizontal component of Earth’s magnetic field is 9 × 10-5T and the resultant magnetic field is 180 × 10-6. Calculate the angle of dip at this place.a)45ob)0oc)60od)30oCorrect answer is option 'C'. Can you explain this answer?
Question Description
At a given place on the Earth’s surface, the horizontal component of Earth’s magnetic field is 9 × 10-5T and the resultant magnetic field is 180 × 10-6. Calculate the angle of dip at this place.a)45ob)0oc)60od)30oCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about At a given place on the Earth’s surface, the horizontal component of Earth’s magnetic field is 9 × 10-5T and the resultant magnetic field is 180 × 10-6. Calculate the angle of dip at this place.a)45ob)0oc)60od)30oCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At a given place on the Earth’s surface, the horizontal component of Earth’s magnetic field is 9 × 10-5T and the resultant magnetic field is 180 × 10-6. Calculate the angle of dip at this place.a)45ob)0oc)60od)30oCorrect answer is option 'C'. Can you explain this answer?.
At a given place on the Earth’s surface, the horizontal component of Earth’s magnetic field is 9 × 10-5T and the resultant magnetic field is 180 × 10-6. Calculate the angle of dip at this place.a)45ob)0oc)60od)30oCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about At a given place on the Earth’s surface, the horizontal component of Earth’s magnetic field is 9 × 10-5T and the resultant magnetic field is 180 × 10-6. Calculate the angle of dip at this place.a)45ob)0oc)60od)30oCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At a given place on the Earth’s surface, the horizontal component of Earth’s magnetic field is 9 × 10-5T and the resultant magnetic field is 180 × 10-6. Calculate the angle of dip at this place.a)45ob)0oc)60od)30oCorrect answer is option 'C'. Can you explain this answer?.
Solutions for At a given place on the Earth’s surface, the horizontal component of Earth’s magnetic field is 9 × 10-5T and the resultant magnetic field is 180 × 10-6. Calculate the angle of dip at this place.a)45ob)0oc)60od)30oCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of At a given place on the Earth’s surface, the horizontal component of Earth’s magnetic field is 9 × 10-5T and the resultant magnetic field is 180 × 10-6. Calculate the angle of dip at this place.a)45ob)0oc)60od)30oCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
At a given place on the Earth’s surface, the horizontal component of Earth’s magnetic field is 9 × 10-5T and the resultant magnetic field is 180 × 10-6. Calculate the angle of dip at this place.a)45ob)0oc)60od)30oCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for At a given place on the Earth’s surface, the horizontal component of Earth’s magnetic field is 9 × 10-5T and the resultant magnetic field is 180 × 10-6. Calculate the angle of dip at this place.a)45ob)0oc)60od)30oCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of At a given place on the Earth’s surface, the horizontal component of Earth’s magnetic field is 9 × 10-5T and the resultant magnetic field is 180 × 10-6. Calculate the angle of dip at this place.a)45ob)0oc)60od)30oCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice At a given place on the Earth’s surface, the horizontal component of Earth’s magnetic field is 9 × 10-5T and the resultant magnetic field is 180 × 10-6. Calculate the angle of dip at this place.a)45ob)0oc)60od)30oCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 12 tests.
|
|
Explore Courses for Class 12 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup