A number has 1 decimal place. It is 49 when rounded off to the nearest...
To find the greatest possible value of a number with one decimal place, we need to look at the digit in the tenths place. We are given that the number rounds off to 49 when rounded to the nearest whole number.
- Tenths place digit:
Since the number rounds off to 49, it means that the digit in the tenths place must be greater than or equal to 5 in order to round up to 49.
- Options analysis:
a) 49.1: If the number is 49.1, it would round to 49 because the digit in the tenths place is 1, which is less than 5. Therefore, this option is not the greatest possible value.
b) 49.4: If the number is 49.4, it would round to 49 because the digit in the tenths place is 4, which is less than 5. Therefore, this option is not the greatest possible value.
c) 48.5: If the number is 48.5, it would round to 49 because the digit in the tenths place is 5, which is equal to 5. Therefore, this option is a possible value.
d) 49.5: If the number is 49.5, it would round to 50 because the digit in the tenths place is 5, which is equal to 5. Therefore, this option is a possible value.
- Conclusion:
Out of the given options, the greatest possible value for the number is 49.5 (option d) because it rounds up to 50 when rounded to the nearest whole number.
A number has 1 decimal place. It is 49 when rounded off to the nearest...
Tetyt
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