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mole fraction of HCl in aqueous solution is 0.1 then what will be the molality of HCl?
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mole fraction of HCl in aqueous solution is 0.1 then what will be the ...
Calculation of Molality of HCl in Aqueous Solution
Given:
Mole fraction of HCl (X(HCl)) = 0.1
Formula to calculate Molality (m):
Molality (m) = (moles of solute) / (mass of solvent in kg)
Step 1: Calculate moles of HCl:
Since mole fraction of HCl is given as 0.1, assume we have 1 mole of the solution.
Therefore, moles of HCl = 0.1 moles
Step 2: Calculate mass of solvent in kg:
Since the mole fraction of HCl is 0.1, the mole fraction of water (X(H2O)) will be 0.9 (as the sum of mole fractions in a solution is always 1).
Given that the mole fraction of HCl is 0.1, we can assume 100 g of the solution.
Therefore, mass of water = 90 g (100 g - 10 g HCl)
Converting mass of water to kg: 90 g = 0.09 kg
Step 3: Calculate Molality of HCl:
Molality (m) = (moles of HCl) / (mass of water in kg)
Molality (m) = 0.1 moles / 0.09 kg
Molality (m) = 1.11 mol/kg
Therefore, the molality of HCl in the aqueous solution with a mole fraction of 0.1 is 1.11 mol/kg.
Given:
Mole fraction of HCl (X(HCl)) = 0.1
Formula to calculate Molality (m):
Molality (m) = (moles of solute) / (mass of solvent in kg)
Step 1: Calculate moles of HCl:
Since mole fraction of HCl is given as 0.1, assume we have 1 mole of the solution.
Therefore, moles of HCl = 0.1 moles
Step 2: Calculate mass of solvent in kg:
Since the mole fraction of HCl is 0.1, the mole fraction of water (X(H2O)) will be 0.9 (as the sum of mole fractions in a solution is always 1).
Given that the mole fraction of HCl is 0.1, we can assume 100 g of the solution.
Therefore, mass of water = 90 g (100 g - 10 g HCl)
Converting mass of water to kg: 90 g = 0.09 kg
Step 3: Calculate Molality of HCl:
Molality (m) = (moles of HCl) / (mass of water in kg)
Molality (m) = 0.1 moles / 0.09 kg
Molality (m) = 1.11 mol/kg
Therefore, the molality of HCl in the aqueous solution with a mole fraction of 0.1 is 1.11 mol/kg.
Community Answer
mole fraction of HCl in aqueous solution is 0.1 then what will be the ...
XHcl=nHcl/(nHcl+nH20)=0.1
XH20=nH20/(nHcl+nH20)=0.9
(1)~mHcl/(36.5g/mol)÷((mHcl/(36.5g/mol)+mH20/18g/mol))=0.1
(2)~mH20/18g/mol÷((mHcl/(36.5g/mol)+mH20/18g/mol))=0.9
by solving the two simultaneously, you get
mH20=4.4gm
mHcl=0.99gm
molality=nHcl/mH20(Kg)
m=0.99gm/(36.5gm/mol)÷(4.4×10^-3)Kg
m=0.027mol/4.4×10^-3Kg
m=6.1mol/Kg
XH20=nH20/(nHcl+nH20)=0.9
(1)~mHcl/(36.5g/mol)÷((mHcl/(36.5g/mol)+mH20/18g/mol))=0.1
(2)~mH20/18g/mol÷((mHcl/(36.5g/mol)+mH20/18g/mol))=0.9
by solving the two simultaneously, you get
mH20=4.4gm
mHcl=0.99gm
molality=nHcl/mH20(Kg)
m=0.99gm/(36.5gm/mol)÷(4.4×10^-3)Kg
m=0.027mol/4.4×10^-3Kg
m=6.1mol/Kg
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mole fraction of HCl in aqueous solution is 0.1 then what will be the molality of HCl?
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mole fraction of HCl in aqueous solution is 0.1 then what will be the molality of HCl? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about mole fraction of HCl in aqueous solution is 0.1 then what will be the molality of HCl? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for mole fraction of HCl in aqueous solution is 0.1 then what will be the molality of HCl?.
mole fraction of HCl in aqueous solution is 0.1 then what will be the molality of HCl? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about mole fraction of HCl in aqueous solution is 0.1 then what will be the molality of HCl? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for mole fraction of HCl in aqueous solution is 0.1 then what will be the molality of HCl?.
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