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The time taken by binary search algorithm to search a key in a sorted array of n elements is
  • a)
    O ( log2n )
  • b)
    O ( n )
  • c)
    O ( n log2n )
  • d)
    O ( n2 )
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The time taken by binary search algorithm to search a key in a sorted ...
Search a sorted array by repeatedly dividing the search interval in half. Begin with an interval covering the whole array. If the value of the search key is less than the item in the middle of the interval, narrow the interval to the lower half. Otherwise narrow it to the upper half. Repeatedly check until the value is found or the interval is empty. It takes a maximum of log(n) searches to search an element from the sorted array. Option (A) is correct.
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The time taken by binary search algorithm to search a key in a sorted ...
Binary Search Algorithm

Binary search is an efficient searching algorithm used to find a specific element in a sorted array. It works by repeatedly dividing the search space in half until the target element is found or the search space becomes empty.

Time Complexity of Binary Search

The time complexity of an algorithm represents the amount of time it takes to run as a function of the size of the input. In the case of binary search, the time complexity is determined by the number of comparisons made during the search process.

Divide and Conquer

Binary search follows a divide and conquer approach to search for a specific element in a sorted array. It starts by comparing the target element with the middle element of the array. If the target element is equal to the middle element, the search is successful. If the target element is smaller, the search continues on the left half of the array. If the target element is larger, the search continues on the right half of the array.

Key Points:
- Binary search works by dividing the search space in half at each step.
- The search space is reduced by half in each iteration, resulting in a logarithmic time complexity.

Time Complexity Analysis

The time complexity of binary search can be analyzed by considering the number of comparisons made during the search process.

At each step, the search space is divided in half, resulting in only one comparison. Therefore, the number of comparisons made during binary search is equal to the number of times the search space can be divided in half until the target element is found or the search space becomes empty.

Key Points:
- The number of times the search space can be divided in half is equal to the number of times we can divide the original search space by 2 until we reach 1.
- This can be expressed as log2n, where n is the size of the search space.

Conclusion

The time complexity of binary search is O(log2n), where n is the number of elements in the sorted array. This means that the time taken by the binary search algorithm to search for a key in a sorted array is proportional to the logarithm of the size of the array. As a result, binary search is highly efficient for large arrays as the search space is reduced by half at each step.
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